add the signal voltages by connecting them in series - to +
An operational amplifier can sum an arbitrary number of signals and produce a single output signal.
Yes. the mean is the average. Since DC is a constant, stable output, the average = the DC magnitude. The average of 1 = 1.
DC generator is used to produce direct current. The basic DC generator have four basic parts 1. A magnetic field 2. A single conductor or loop 3. A commutator 4. Brushes
help me now !!
1. start 2. sum=0 3. input n 3. for i=1 to n do 4. input x 5. sum=sum+x end of for (3) 6. avg=sum/n 7. output sum, avg 8. stop
Capacitors don't 'block' a.c. signals; they block d.c. signals. But there are lots of different reasons for using capacitors apart from their ability to block d.c. signals.
To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END
int main() { int i,j,sum,k; for(i=1;i<=5;i++) { k=1; sum =0; for(j=1;j<=i;j++) { sum = sum+(i*k); k=k*10; } cout<< sum; cout<< "\n"; } }
1.Start 2. Input a,b,c 3. Sum = a+b+c 4. Average = sum/3 5. Output - Sum,Average 6. Stop
Pulsating dc. Imagine a sine wave that goes above and below the zero voltage level. A 1/2 wave rectifier clips all the waves either above or below zero voltage. You basically have a hump for 1/2 a cycle then zero voltage for 1/2 a cycle, and then another hump and so forth.
Their sum is 1.Their sum is 1.Their sum is 1.Their sum is 1.
The 2-bit adder has two input lines and two output lines.The two input lines are the two bits to be added, call them "Bit-A" and "Bit-B".The two output lines are "sum" and "carry".Here are the states of the "sum" and "carry" outputs, for every combination of inputs "Bit-A" and "Bit-B":Bit-A . . . Bit-B . . . Sum . . . Carry0 . . . . . . . . 0 . . . . . . 0 . . . . . . 00 . . . . . . . . 1 . . . . . . 1 . . . . . . 01 . . . . . . . . 0 . . . . . . 1 . . . . . . 01 . . . . . . . . 1 . . . . . . 0 . . . . . . 1The Boolean functions for the two output lines are:SUM = [ (Bit-A) XOR (Bit-B) ]CARRY = [ (Bit-A) AND (Bit-B) ](Actually, I think the "adder" only has one output line, called "sum"; if it also has the "carry" output,then it's called a "full adder". To me, a full adder is a snake plus a dead frog.)