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The Gibbs free energy change is calculated from the expression
Δ G = Δ H - T(Δ S)

For the oxidation of iron, assuming you mean heating iron in air, where the product is black iron oxide,

3Fe + 2O2 --> Fe3O4

you need to find the enthalpy and entropy changes, which are

Δ H (formation) = - 1118.4 kJ/mol

Δ S (formation) = - 345.5 J/mol/K

Substituting into the first equation, remembering to divide the entropy value by 1000 because it's in J per mol per kelvin, not kJ, and converting the 25 degrees C to kelvin, we get:

Δ G = -1118.4 kj - 298 (- 345.5)/1000 kJ

= - 1015.441 kJ

http://www.docbrown.info/page07/delta3SGc.htmΔ

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Q: How do you use the Gibbs free energy equation to find the Gibbs free energy change for the oxidation of iron at 25 degrees C?
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