To convert from binary to octal, bitwise AND the binary value with 0x8 (00000111 in binary) and push the value onto a stack. Right-shift (>>) the binary value by 3 bits and repeat until the binary value is zero. Pop the stack to build the left-to-right digits of the octal value.
Using 10110100 as an example:
10110100 & 00000111 = 00000100
10110100 >> 3 = 00010110
00010110 & 00000111 = 00000110
00010110 >> 3 = 00000010
00000010 & 00000111 = 00000010
00000010 >> 3 = 00000000
Popping the values in order reveals 00000010, 00000110 and 00000100 (decimal 2, 6 and 4 respectively).
Thus 10110100 binary is 0264 octal.
If necessary, pad the value with zeroes so the number of bits is an exact multiple of 3. Then divide the binary value into groups of 3 bits. Convert each group to its corresponding octal digit as follows: Bin = Oct 000 = 0 001 = 1 010 = 2 011 = 3 100 = 4 101 = 5 110 = 6 111 = 7 Example 1: 16-bit value: 1011101101100011 3-bit groupings: (00)1 011 101 101 100 011 Octal digits: 1 3 5 4 3 Octal value: 13543 Example 2: 24-bit value: 010111011010010101011010 3-bit groupings: 010 111 011 010 010 101 011 010 Octal digits: 2 7 3 2 2 5 3 2 Octal value: 27322532
trivial.
Binary is a base 2 number system, while octal is base 8. This happens to make conversion between binary and octal fairly trivial, although more complex than conversion to hexadecimal. To convert to octal from binary, take each three bits, starting from the least significant bit, and convert them to their octal equivalent. Examples: 25510 = 111111112 = 11 111 111 = 3778 17410 = 101011102 = 10 101 110 = 2568 You can repeat this process for as many bits as you need. A 24-bit number should translate into 8 octal numbers, for reference.
C++ does not support octal encoding within source code (only decimal and hexadecimal are supported), so the octal must be represented with a string. The binary output must also be a string. Every octal digit represents three bits of binary, thus the binary output string will always be three times the length of the octal input string. The loop will begin with the octal character at index 0 and work through each character from left to right. On each iteration, the binary output string will be appended with a 3-character string, as follows: octal = binary "0" = "000" "1" = "001" "2" = "010" "3" = "011" "4" = "100" "5" = "101" "6" = "110" "7" = "111" Thus octal input "437" will begin with the "4" producing an output of "100". On the next iteration, "3" will append "011" to produce "100011". On the final iteration, "7" will append "111" to produce "100011111".
A45C: Decimal = 42076 Octal = 122134
In binary this number is equivalent to 11111000011 while in octal it is 3703
Octal = 52746757 Binary = 101010111100110111101111
1470 octal = 001 100 111 000 binary
Starting from the right hand end, take the digits in groups of 3 and convert each group to its octal equivalent (which for this task will always be the same as decimal). eg 110 is octal 6
Don't. 889 is not an octal number.
1111111010 = octal 1772
Octal 76 = 111110
221122: Binary = 1000100001000100100010 Octal = 10410442 Decimal = 2232610
10111001100001000
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134.105
15173