How do you write a c program that computes the results of ten students for any given four subjects grading their results from a to you?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int n, i,a[100],sum=0;

float avg;

printf("Enter number of students");

scanf("%d",&n);

printf("Enter the marks score by students one by one");

for(i=0;i<n;i++)

{

scanf("%d",&a[i]);

sum=sum+a[i];

}

avg=sum/n;

printf("The average is %f", avg);

getch();

}

Answer 2

You can use the accumulate function to determine the sum of elements in any data container, including an array (provided the container type supports binary operator+). For example:

std::array<int, 6> a {5,9,2,3,4,1};

int sum = std::accumulate (a.begin(); a.end());

int avg = sum / a.size();

assert (sum==24);

assert (avg==4);

Answer 3

#include<stdio.h.

int l,m.n.o.p.r.s

main()

{

print f("enter ten students;");

print f("enter x<30=u;);

scan f("l,x<30=u);

print f("input x>29 but less that 40=e;");

scan f("m,x>29 but less than 40=e");

print f("enter x>39 but less than 50=d;")

scan f("n,x>39 but less than 50=d);

print f("input x>49 but less than 60=c;");

scan f("o,x>49 but less than 60,");

print f(" input x>59 but less that 70=b;");

scan f("p,x>59 but less than 70;");

print f("enter x>69 to 100=a;");

scan f ("q,x>69 to 100;");

/*input number of subjects*/

print f ("enter four subjects;");

scan f("%d," &r);

/*grade the results of each students per subject*/

s=graded results of each student;

print f("grade results for a up to u of each student;");

return 0

}

Answer 4

1. Declare a float variable for storing the sum of the three marks, and set it to zero.
2. Make a loop that iterates three times. A for loop would suffice.
3. In that loop, prompt the user to enter a mark. If you're not worried about memory vulnerabilities then simply using printf and scanf would do. Add the entered value to the float that you declared for storing the sum.
4. After the loop is complete, divide that sum by three.
5. Output the result (again, printf would probably suffice).

So a quick hen-scratch (untested, and I haven't done any real C Programming in years):

#include

int main void(int argc, char *argv[]){

float tally = 0, mark;

int n, numStudents = 3;

for(n = 0; n < numStudents; n++){

printf("Please enter the mark for student #%i: ", n + 1);

scanf("%f", &mark);

tally += mark;

}

printf("The average mark of the %i students is %f\n", tally / numStudents);

return 0;

}

Answer 5

You can use the accumulate function to determine the sum of elements in any data container, including an array (provided the container type supports binary operator+). For example:

std::array a {5,9,2,3,4,1};

int sum = std::accumulate (a.begin(); a.end());

int avg = sum / a.size();

assert (sum==24);

assert (avg==4);

Answer 6

To write a C program to find the total and average for seven subjects, sum the seven subjects to get the total. Divide the total by seven to get the average.