There will a part like this:
typedef struct Point { double x, y; } Point;
typedef struct LineSegment { Point from, to; } LineSegment;
The Socket class in Java is an endpoint in a standard TCP connection. The Socket class implements methods which take care of all the overhead required with TCP communication.
A data strucutre is classified into two categories: Linear and Non-Linear data strcutures. A data structure is said to be linear if the elements form a sequence, for example Array, Linked list, queue etc. Elements in a nonlinear data structure do not form a sequence, for example Tree, Hash tree, Binary tree,etc. There are two ways of represneting linear data strucutresin memory.One way is to have the linear relationship betweent he elements by means of sequential memory locations. Such linear strucutres are called arrays. The other way is to have the linear relationship betweent he elements represnted by means of links.Such linear data strucutres are callled linked list.
The data link layer (2nd layer), the network layer (3rd layer) and the transport layer (4th layer) each handle their own specific errors, which should prevent errors in both directions. Any untrapped errors will result in a corrupt transmission which may or may not be handled by the appropriate endpoint, dependant upon the protocol.
A line is basically a combination of two joined rays pointing in opposite directions. A line has no endpoints and a line segment has two. <--------------> line ---------------> or <------------ ray .________. line segment (It's supposed to be a line with dots at the end to signify endpoint)
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If you are only given one endpoint and a midpoint, you know what the middle of the line segment is. Since the midpoint is half of what the line segment's length is, all you have to do is find the distance between the endpoint given and the midpoint, then add that coordinate to your midpoint and get your other endpoint. For example: Endpoint A: (4,5) Midpoint: (6,8) Distance between: (2,3) Add (2,3) to (6,8) and get Endpoint B: (8,11).
A line with only one endpoint is a ray. One end has a point, and the other has an arrow to represent how the line continues forever.-------------------------->
If the coordinate of A is x, and that of the midpoint of AB, M, is m then the distance AM is m-x so the distance AB = 2*(m-x) So the coordinate of B is x + 2*(m-x) = 2m-x For coordinates in more than one dimension, apply the above rule separately for each dimension.
The direction of missing endpoint is the same as the direction from the known end point to the midpoint. The distance from the midpoint to the missing endpoint is the same as the distance from the known end point to the midpoint. In coordinate geometry it is simple. If the known end point is (p, q) and the mid point is (r, s) then the missing point is (2r - p, 2s - q).
Each coordinate of the midpoint of a straight line segment is the arithmetic mean of the coordinates of the endpoints. So the y-coordinate is (0+15)/2 = 7.5
The endpoint has no dimension. It has no endpoint.
If you mean endpoints of (0, 0) and (0, 15) then the midpoint is at (0, 7.5)
It is really simple. A follow the steps below: 1) Add up your X1 AND X2 from both endpoints and divide by two. This will be your X coordinate for the midpoint. 2) Add up your Y1 + Y2. Divide it by two. This will be your Y coordinate for the endpoint. Hope this helps :)
No, lines are ongoing, and have no endpoint.
If you mean endpoint (6, 9) and midpoint (7, 6) then the other endpoint is (8, 3)
Use the midpoint formula.( x1 + x2 / 2 , y1 + y2 / 2 )For example, if you were given segment QR with midpoint M(-1, -1) and endpoint Q(-8, 10):(-1, -1) = ( x1 + -8 / 2 , y1 + 3 / 2)X COORDINATE--------------------1 = x1 + -8 / 2-2 = x1 - 86 = xY COORDINATE--------------------1 = y1 + 10 / 2-2 = y1 + 10-12 = y
The answer depends on what the endpoint is shared with!