liter = unit of volume
mole = unit of concentration
345 liters = 91.14 US gallons.
The molarity of the solution is 40.1 M. This is calculated by dividing the moles of solute (345 mol KCl) by the volume of solution in liters (8.6 L).
345 liters = 91.14 US gallons.
moles of acid = moles base = moles base/liter x liters of base used
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
L = mL/1000.0 345/1000 = .345 Liters. Divide by 1000 = 0.345 L There are 1000 milliliters in 1 liter. One milliliter is 0.001 liter
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
1 litre = 1000 millilitres. 345 millilitres = 0.345 litres.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------