Here is an example of factorising:
3ab+9b
The answer would be: 3b(a+3)
First, in 3ab+9b, you have to find LIKE TERMS. Like Terms are numbers, letters, etc. that are present in both the 'sides' (3ab is one side, 9b is the other). b is present in both. Now, you may be wondering about the 3 in the answer - this one: 3b(a+3). This 3 is here because it is the highest common factor for both 3 and 9 in (3ab+9b). In other words, three goes into both 9 and 3.
9 divided by 3 = 3 (this part - 3b(a+3) )
3 divided by 3 = 1 (this part - 3b(a+3) )
You don't need to put 1a, just a, because they are the same.
I hope you understood this. If not, get your teacher or a friend to explain it :)
Meanwhile, test yourself with these:
4ab+3a
7b+28ab
6ab2 + 7a2 b (this one's harder!)
factorising
no bloody clue
Expanding Brackets
30
Completing the square will work when the solutions are irrational. Finding irrational factors is extremely difficult.
-3
To find the common factor when factorising, look for any common factors that can be divided evenly from all the terms in the expression. Divide each term by this common factor, and then factorise the resulting expression further if possible. This will help simplify the expression and make it easier to work with.
Factorising 15x-27xy gives 3x (5 - 9y).Factorising is to express a number or expression as a product of factors.When factorising always look for common factors. To factorise (15x-27xy) look for the highest factor between the two terms (3x). 15x - 27y = 3x (5 - 9y)
(a + x)(b + c)
5(7a + 2)
There is no simple way of factorising AB - CD
No, it is not. It is factorising - which is more related to dividing.