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These have to do with the hydraulic density. In automobile, the density increases therefore making the hydraulic ratio to displace more than any hydraulic ratio in a displacement.
By "Hydrostatic" systems one tends to mean "closed loop hydraulic systems". That is hydraulic systems comprising a pump and motor hwere the pump supplies the motor whose return side supplies the pump. The speed and direction of rotation of the hydraulic motor being changed according to the displacement angle of the variable displacement axial pison pump. "Open loop hydraulic systems" on the other hand comprises various motors often one or more "linear motors" (hydraulic cylinders). When using hydraulic cylinders in hydraulic systems one needs a reservoir to be able to hold the various volume need of the cylinder. (the displacement on the piston side is usually bigger than the rodside). The reservoir needs a "breather" due to the varous displacement needs hence the "open system".
Instead of hydraulic pumps, hydraulic gear motor does not work. Hydraulic pump hydraulic motor blade is used instead.
how to calculate hydraulic motor torque
Internally, they're pretty much the same. The difference is the operation expected of it - a hydraulic pump converts mechanical energy to fluid energy, whereas a hydraulic motor converts hydraulic energy to mechanical energy.
These have to do with the hydraulic density. In automobile, the density increases therefore making the hydraulic ratio to displace more than any hydraulic ratio in a displacement.
yes.only positive displacement pumps can be used in hydraulics
Displacement is the measure of how much fluid it takes to turn the hydraulic motor shaft per revolution. It is typically expressed in cubic inches or cubic centimeters per revolution. Given the same flow rate and pressure, a larger displacement motor will turn slower than a smaller displacement motor. A larger displacement motor will also produce higher torque than a smaller motor. So as displacement increases, torque goes up and speed goes down. This makes sense as torque multiplied by speed equals horse power. For a same input horsepower (pressure times flow), if one value did not vary as the inverse of the other, the conservation of power would not be met.
By "Hydrostatic" systems one tends to mean "closed loop hydraulic systems". That is hydraulic systems comprising a pump and motor hwere the pump supplies the motor whose return side supplies the pump. The speed and direction of rotation of the hydraulic motor being changed according to the displacement angle of the variable displacement axial pison pump. "Open loop hydraulic systems" on the other hand comprises various motors often one or more "linear motors" (hydraulic cylinders). When using hydraulic cylinders in hydraulic systems one needs a reservoir to be able to hold the various volume need of the cylinder. (the displacement on the piston side is usually bigger than the rodside). The reservoir needs a "breather" due to the varous displacement needs hence the "open system".
It means how much oil is needed to make the motor turn one full revolution. If you have a 32 Cubic Inch Hydraulic Motor, you would need to push 32 cubic inches of oil through that motor to turn it once. Using the same hydraulic pump, a smaller cubic inch motor would cause higher speed, but less torque.
Instead of hydraulic pumps, hydraulic gear motor does not work. Hydraulic pump hydraulic motor blade is used instead.
how to calculate hydraulic motor torque
Instead of hydraulic pumps, hydraulic gear motor does not work. Hydraulic pump hydraulic motor blade is used instead.
how to calculate hydraulic motor torque
Only the sweep is linear cylinder. Motor rotates the hydraulic oil pressure.
there is no such thing as a hydraulic motor........there is, however, a hydraulic pump. there is such thing as a hydraulic motor. the hydraulic pump will pump oil to the motor and a pressure differential across the motor causes the fluid power to be converted to mechanical power. the power output of the motor is determined by the motor's pressure, flow, displacement, and torque. ________________________________________________________________ I believe the above post is wrong in part and right in part. Choosing a hydraulic motor to replace you 16hp gas engine requires more information than just the horsepower. It would be helpful to know many other factors, such as required torque needed in the application and the rpm. When these play a part in overall horsepower, knowing these pieces of information will help find a motor. When I've purchased motors in the past, I've used this website. They are very thorough and well-priced. www.surpluscenter.com What I took away from the response above, is the person was trying to tell you how to replace a whole hydraulic system. However, its needed in your case, so long as you have a new power source for the hydraulic motor. (IE: a gas engine to power a hydraulic pump, then lines from the hydraulic pump to the hydraulic motor (insert a valve if you wish to control motor speed and/or direction), and then the hydraulic motor. Its important to have a hydraulic tank with enough capacity to hold all the fluid which will be in motion. The more devices in the system, the bigger the tank. Hope this helps!!
It is a hydraulic motor housing containing a vane that turns the shaft when hydraulic fluid is pump through the motor.