It doesn't, really. The power loss occurs via the resistance of the copper windings and eddy currents in the magnetic core. More details are given in the earlier answer to the same question.
It doesn't, really. The power loss in transformers is broken down into copper loss and iron loss. The copper loss comes from the resistance of the windings in the transformer and depends on the load current, while the iron loss in the magnetic core depends on the magnetic flux density and is constant if the supply voltage is constant.
ideal transformer is that which has no power losses.if any transformer transfer power to secondary without power loss then that call a ideal transformer
ideal transformer is that which has no power losses.if any transformer transfer power to secondary without power loss then that call a ideal transformer
A: Absolutely a power transfer will have an internal loss of IR . for a power transformer the loss can be as much of 20% or more if other magnetics are involved like iron screw holding the lamination together. Usually brass is used to reduce that loss.
These two tests are performed on a transformer to determine (i) equivalent circuit of transformer(ii)voltage regulation of transformer(iii) efficiency of transformer. The power required for theseOpen Circuit test and Short Circuit test on transformeris equal to the power loss occurring in the transformer.
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
If by 'loss current' (?) you mean the 'copper losses', then there is no practical way of doing so without reducing the load current. Perhaps you should explain what you understand 'loss current', in the context of a step-down transformer, to mean?
A: there is no formula the gain of the amp is just reduced by the transformer turn ratio minus efficiency or loss. the transformer is for isolation and impedance matching
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
The short-circuit test runs the rated current through the windings of the transformer to measure the copper-loss, or power lost in the winding resistances. Because the transformer is run at low voltage for this test, there is very little additional power loss in the iron core of the transformer.
Maximum efficiency of a power transformer occurs when copper loss equals to iron losses. Decrease in current does not result in increase in efficiency unless the copper loss was more than iron loss and the decreased current made the copper loss is reduced and became equal to iron loss at some point.
the efficiency is maximum in a transformer when no load loss is equal to load loss.