To avoid voltage drop in the coil.
One thing you could do is look up the datasheet for the motor and/or contact the manufacturer of the motor. Also, if you know the guage of wire, you can calculate it based on the resistance of the coils on the motor/generator or on the coils of the transformer
The inductance of the transformer is much higher than the resistance of the transformer, resulting in very low real power losses (in watts), but some reactive power (vars).
Transformer coils are normally used to step down power from high power lines to a power you can actually use in your house. This works through the ratio of windings on a coil to the windings on the output side.
A true voltage transformer is not designed for power applications; it will only supply so many VA to your charger. I would suggest you purchase a power transformer for this application. You'll need to rectify the AC voltage, and minimize the ripple. Rectifiers are used for the first part, capacitors, varistors, and power transistors can be used to minimize the ripple.
A Linear power transformer coil? use an Ohm meter and check the resistance of the coils. No resistance is an open circuit. Also check for a cross circuit from one side of the transformer to the other.
Measuring No-LoadIn theory the no-load current of a transformer is zero. But in practice there is iron loss and core loss in the transformer, so there is power loss. Connect an ammeter in series with the stabilizer to measure the no-load current. Check your energy meter at no-load to see how much power is consumed. Ohms law: I(Amps) = E(voltage) divided by R(resistance). In the case of coils (transformer), the resistance of the coil would simply be the total impedance (Z). If I am remembering this correctly, you get, I=E/(R+Z)
If you mean how to use a resistance of so much power then it can be easily done through a step-down transformer which lowers the voltage supply and hence the power.
minimize congestion, stability margin improvement, line overload reduction, power flow control
There is none. There is a relationship between voltage and current and turns ratios in a transformer. But this rule remains - power in = power out. You don't get anything for free.
Power is normally transmitted at high voltage through step up/step down transformers to minimize the power losses in the transmission lines (this is one reason anyway). Since power loss is equivalent to the resistance of the conductor times the current squared, stepping up the voltage by a factor of two cuts the transmission losses by a factor of (2^2 = ) 4.
Due to the heavy coils found inside the body also you will find an insulation that is oil type, that s why it s so heavy , but if u look at the dry type transformer u will find it so light and compact that s all i know my sir Eng: Amr <<>> The reason that power transformers are so heavy is from the steel laminations that the core of the transformer is built from. The outside transformer is constructed out of steel which also adds to the weight. Transformer coils these days are using aluminium wire for the primary and secondary wraps. This keeps the weight down and also helps in preventing copper theft.
ideal transformer is that which has no power losses.if any transformer transfer power to secondary without power loss then that call a ideal transformer