It cannot N is Nitrogen where as Na is Sodium, they are two totally different elements
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
0.1125
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
Molar mass of NaOH = ~40 g/mole. Depending on what volume of 0.2 N NaOH you want, the amount will vary. Assuming you want to make 1 liter, then 0.2 mole/L x 40 g/mole = 8 grams.So, weigh out 8 grams NaOH and dissolve in enough water to make a final volume of 1000 ml. For 100 mls of 0.2 N NaOH, weigh 0.8 grams and dissolve in enough water to make a final volume of 100 ml.
add 10 grams of NaoH into 1000 ml water, it will give you NaoH of 0.25N. As for making 1N solution you need to disolve 40 grams of NaoH into 1 litre water.
Take 60 gm NaOH (100%) disolve it in distilled water, and make up to 2.0 liter by distlilled water.the prepared solution is 0.75 N NaoH Solution.
Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)
the mixture turn purple. cuso4 n naoh is use to detect the presence of peptide bonds in protein
mehedi hasan
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
1 millimolar = 0.001 M NaOH ( a base, remember ) - log(0.001 M NaOH) = 3 14 - 3 = 11 pH ----------
Take 10 ml of 1 N NaOH and dilute to 1000 ml with D.I. H2O