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There is the 1/r law for sound pressure and distance. Double the distance from a sound source gives 6 dB less sound pressure level. Scroll down to related links and look at "Sound pressure and the inverse distance law ".

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15y ago
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12y ago

A doubling of distance from the sound source in the direct field will reduce the "sound level" by 6 dB, no matter whether that are sound pressure levels or sound intensity levels. This will reduce the sound pressure p (sound field quantity) to 1/2 (50 %) and the sound intensity I (sound energy quantity) to 1/2² = 1/4 (25 %) of the initial value.

The inverse distance law 1/r shows the distance performance of field quantities and the inverse square law 1/r² shows the distance performance of energy quantities. Squared sound field quantities are proportional to sound energy quantities; e.g. p² ~ I.

The sound pressure p changes (decrease - drop - fall) with 1/r over distance. Sound pressure level decreases by (−)6 dB per doubling of distance from the source to 1/2 (50 %) of the sound pressure initial value.

Sometimes it is said that the sound pressure would change with 1/r². That is really wrong.

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Q: How does sound vary with distance?
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What happen to the loudness of sound as the distance incrase between a person and the source of the sounds?

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