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If the power is constant, the amplitude will decrease.
The answer depends upon the conditions of the environment. If the available energy to the wave generator is unbounded, then there is no impact on amplitude as frequency increases. However if total energy rate is constant, then the amplitude must decrease as frequency increases in order to maintain the same energy output.
The greater the energy,the larger the frequency&the shorter (smaller) the wavelength.Given the relationship between wavelength&frequency - the higher the frequency,the shorter the wavelength-it follows that short wavelengths are more energetic than long wavelengths.
-- Frequency and wavelength are inversely proportional. Their product is constant, and is the speed of the wave. They're entirely unrelated to amplitude or energy. -- A wave with greater amplitude carries more energy than one with smaller amplitude does. -- IF your wave happens to be an electromagnetic one, THEN the energy carried by each quantum is proportional to the frequency.
Yes, energy transfer for mechanical waves is dependant on frequency as well as amplitude. Energy of electromagnetic waves, however, does not rely on frequency but solely on amplitude.
If the power is constant, the amplitude will decrease.
The answer depends upon the conditions of the environment. If the available energy to the wave generator is unbounded, then there is no impact on amplitude as frequency increases. However if total energy rate is constant, then the amplitude must decrease as frequency increases in order to maintain the same energy output.
The greater the energy,the larger the frequency&the shorter (smaller) the wavelength.Given the relationship between wavelength&frequency - the higher the frequency,the shorter the wavelength-it follows that short wavelengths are more energetic than long wavelengths.
-- Frequency and wavelength are inversely proportional. Their product is constant, and is the speed of the wave. They're entirely unrelated to amplitude or energy. -- A wave with greater amplitude carries more energy than one with smaller amplitude does. -- IF your wave happens to be an electromagnetic one, THEN the energy carried by each quantum is proportional to the frequency.
It doesn't, from the equation E = h*f (E is energy, h is Planck's constant, f is frequency) you can clearly see that energy is a function of frequency, not amplitude (intensity). Therefore, it doesn't even matter what the relationship between stopping potential and energy is, because it will only depend on frequency, which is sufficient knowledge to answer this question.
Frequency.
Yes, energy transfer for mechanical waves is dependant on frequency as well as amplitude. Energy of electromagnetic waves, however, does not rely on frequency but solely on amplitude.
Sound energy travels in waves and is measured in frequency and amplitude
The energy of a photon is directly proportional to its frequency. (The proportionality constant is Planck's Konstant.) If one photon has double the wavelength of another, then its frequency is 1/2 the frequency of the other one, and its energy is also half.
By increasing its amplitude and/or frequency.
They are independent quantities. Amplitude decides the intensity ie energy content of the wave and frequency is different right from amplitude. If the maximum amplitude,E, is known then the instantaneous amplitude, e, can be found by e=E*sin(2*pi*f*t) where f is the frequency and t is the time in seconds from the start of the sine wave. Note that the angle in brackets is in radians. -------------------------------------------------------------------- Hi there is no such a term "maximum amplitude". Amplitude itself is the maximum displacement. For a fixed frequency and fixed amplitude, as time passes then the displacement e varies as fractiion of max E. That is all. E is constant and f is another constant. They are not directly related in any way.
Frequency