0
How does the loading effect of an ammeter in a low resistance circuit compare to the loading effect in a high resistance circuit?
Wiki User
∙ 7y ago
The voltmeter has an internal resistance, which should be as high as possible. As this resistance draws current from the circuit under test, it will affect circuit operation. This is more pronounced in a high impedance circuit because the current drawn flows through higher resistances.
Wiki User
∙ 7y ago
Add your answer:
Earn +20 pts
What is the maximum volt-ampere loading permitted on a 20-ampere branch circuit with a continuos load is?
The wattage of the circuit presuming that the circuit voltage is 120 volts. 20 x 120 = 2400 watts. Circuit loading on a continuous load is 80% so 2400 watts x .8 = 1920 watts
What instrument measures a circuit that is sensitive to loading?
A high-impedance voltmeter is most appropriate.
How many 8 milliamp lamps can you put on a 20 Amp circuit?
There are 1,000 miliamps in 1 amp. As the NEC limits you to loading a lighting circuit to no more than 80% you can have 16 amps or 16,000 miliamps on that circuit. That would mean you can have 2,000 lamps of 8 miliamps each.
How many 15 amps sockets can i connect in a single circuit?
Circuit loading In Canada the code rule is, there shall be not more that 12 outlets on any 2 wire branch circuit. Such outlets shall be considered to be rated at not more that 1 amp per outlet. Where the connected load is known, the number of outlets may exceed 12 providing the load current does not exceed 80 % of the rating of the over current device protecting the circuit.
Why does plugging too many appilances into the same circuit cause too much current to flow through the circuit what will happen as a result?
Each appliance has its own amperage. This can be shown by looking at the label of each appliance. A circuit is protected by a breaker which has a trip limit. By continually adding more amperage from different appliances, the circuit becomes overloaded. When the circuits limit is reached because of the additive effect of more appliances to the circuit the breaker will trip. This disconnects the appliance loads from the distribution panel supply and prevents over loading of the conductors of that circuit. Without removing some of the load amperage, the breaker will keep tripping when reset.
How can an ammeter loading effect the circuit under test?
Since internal resistance of the ameter will increases the resistance of the circuit. Thus decreasing the current giving an errorenous reading.
What is a description of the loading effect of an ammeter?
loading of an ammeter in a circuit decreases the flow of current,so it has to be calculated to reduce expected errors in the operations
How can you measure internal resistance of car battery?
You measure it indirectly using a known load resistance and measuring supplied current. Loading of the ammeter should be known as well, and the load resistance should be made relatively small to get accurate results.
What will happen if the voltmeter was inserted in place of an ammeter?
You would load the circuit, and it is likely it would not operate correctly. A volt meter is designed to have a very high resistance between the two probes; an ammeter is designed to have a very low resistance. For instance, say you have a 120 watt light bulb that runs on 120 volts (you would then draw ~1 amp of current). If you tried to measure this with a meter that has .1 ohm resistance on ammeter setting, and 1,000,000 ohms on volt meter: Error due to loading: ammeter: .1 / (120 + .1) = .08%; Current will be .999Amps, power to the light bulb will be 119.9 watts Volt meter: 1,000,000/ (120 + 1,000,000) = 99.9%; current will be 120micro Amps, power to the light bulb will be 14.4 milliwatts (the light bulb will not appear to be on).
How does the loading effect of a voltmeter in a high-rsistance circuit compare to the loading effect in a low-resistance circult?
The voltmeter has an internal resistance, which should be as high as possible. As this resistance draws current from the circuit under test, it will affect circuit operation. This is more pronounced in a high impedance circuit because the current drawn flows through higher resistances.
What is loading affect of multimeter?
'Loading effect' applies to voltmeters, or to multimeters when set to measure voltage. It describes the change in a circuit's resistance when the resistance of the voltmeter is taken into account. It's effect is to cause the resulting measuredvoltage to be different from the actual voltage which would appear without the voltmeter connected. The loading effect is minimised by ensuring that the internal resistance of the voltmeter is significantly higher than the resistance of that part of the circuit to which it is connected. For general voltage measurement, this is usually the case anyway, but when measuring circuits which, themselves, have very high resistance care must be taken over the choice of voltmeter to be used.
Why a circuit will produce a loading effect?
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
What is the difference between a voltage divider circuit and voltage regulator I was told if the circuit consumes low current then the voltage divider can be used what does that mean?
A: that is true for less current a divider is OK it has to do with the series resistance and loading if the loading is forever fixed and the source is also fixed at a value then a divider can be used no matter what the current is.
How you can minimize the loading effect on voltmeter?
Loading refers to the phenomena that occurs when a load circuit having low effective impedance is connected to a supply circuit having higher effective impedance.
What is the maximum volt-ampere loading permitted on a 20-ampere branch circuit with a continuos load is?
The wattage of the circuit presuming that the circuit voltage is 120 volts. 20 x 120 = 2400 watts. Circuit loading on a continuous load is 80% so 2400 watts x .8 = 1920 watts
How you can eliminate loading effect in amplifiers?
By increasing the input impedance of amplifier.
What is the difference between direct loading and phantom loading?
Phantom loading consits of supplying the pressure circuit from a seperate low voltage supply. It s possible to circulate rated current through the curent circuit with a low voltage supply as the impedance of this is very low. therfore the total power required for testing the meter is compartively smal with phantom loading.
