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What is the total voltage drop across a set of resistors in series?
Wiki User
∙ 15y ago
Simply add all of the component's resistances together and that will give you circuits total resistance. If you're dealing with a 'series-parallel', or 'parallel' circuit, the equations will change, but in a simple series circuit, the total resistance is just the total of all the component's resistance.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoVoltage drop across a resistor, by Ohm's law, is voltage equals current times resistance.
Since it is a series circuit, by Kirchoff's current law, every resistor in the series circuit will have the same current.
Since it is a series circuit, by Kirchoff's voltage law, the sum of the voltage drops across all resistors equals the voltage of the voltage source.
In fact, you can use those three facts to solve the system of simultaneous equations, and derive the equation of resistance in series...
RSERIES = summationI=1toN (RI)
Wiki User
∙ 15y agoThe total voltage drop across a set of resistors in series is the sum of voltage drops across each individual resistor.
Wiki User
∙ 14y agoThe voltage drops across each resistance sum to the total voltage.
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∙ 13y agoA: The source voltage will equal the addition of all the voltage drops across every component in a series circuit
Wiki User
∙ 10y agoResistors in series add.
RTOTAL = summationI=1toN (RI)
Wiki User
∙ 11y agoThey would be the same.
Wiki User
∙ 9y agoUse Ohm's Law:
V = I x R.
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Did the the total voltage across the resistors does not depend on the resistor value?
It depends on where and how the resistor is placed in a circuit. A string of series resistors will split the voltage across all them depending on their values. All of the resistors in parallel will have the same voltage across all of them no matter what their resistance is.
What happens to the current through a series circuit as more resistors are added in series?
If the bulbs are in a series circuit the voltage drops at each bulb drops as additional bulbs are added. In a parallel circuit the voltage is constant no matter how many bulbs are added.
When a 30.0-V emf device is placed across two resistors in series a current of 14.0 A is flowing in each of the resistors. When the same emf device is placed across the same two resistors in parallel?
There is insufficient information in the question to answer it. 30 volts generating 14 amperes means the two resistors have a total series resistance of 2.143 ohms. Since no relationship was stated, we don't know the value of the individual resistors. If the two resistors had the same resistance, the net parallel resistance would be 0.536 ohms, and a current of 56 amperes would flow.
What is the total current flowing through a 45 ohm resistor 1.4 amps and 20 ohm resistor 1.8 amps?
That depends on several factors that aren't specified in the question: -- whether the resistors are connected to each other -- whether they're connected in series or in parallel -- the voltage applied across the ends of the circuit While these two resistors are in their plastic packages hanging on the wall at Radio Shack, the total current flowing through both of them is zero.
What happens to the voltage as more bulbs are added in series?
The total voltage should not change in this case.
Did the the total voltage across the resistors does not depend on the resistor value?
It depends on where and how the resistor is placed in a circuit. A string of series resistors will split the voltage across all them depending on their values. All of the resistors in parallel will have the same voltage across all of them no matter what their resistance is.
What is the voltage reading of two resistors in series that has a total resistance of 75 K?
The voltage across the ends of the series combination is 75,000 times the current through it.
What are the relation between individual voltage and the total voltage when resistors are connected in series?
when A resistance is connected across the supply voltage, total input vooltage will be drop in the resistance when the resistances are connected across the supply voltage, total input vooltage will be devidedacross the resistances. IF R value will be high ,drop also high. IF R value wll be low ,voltage drop will be less.
What are the relations between individual voltages and the total voltages when resistors are connected in series and in parallel?
-- The current in each individual resistor is (voltage across the whole circuit) divided by (the resistance of the individual resistor). -- The current in any individual resistor is less than the total current in the circuit. -- The total current in the circuit is the sum of the currents through each individual resistor.
Definition of voltage divider?
Basically, if you have two resistors in series, then the total resistance is Rt = R1+R2. According to Kirchhoff's law, the total current entering a junction must be equal to the total current leaving it, so for a series circuit the current is the same in both resistors. From Ohm's law V=IRt and so from above V = I(R1+R2). This means that that total voltage in the circuit, V, is equal to the sum of the voltages across each resistor V1=IR1 and V2=IR2. This "divides" the voltage, so that for a 30V supply with two resistors of 10 ohms and 20 ohms respectively, the voltage across the first resistor will be 10V and the voltage across the second will be 20V. In this way a component requiring a lower voltage than the supply voltage can tap off from one of the resistors.
How would you connect a resistor in order to reduce an LED's applied voltage?
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
What is the max voltage for 3 50ohmn resisters?
It depends on the power rating of the resistors. The total power of a series or parallel combination of resistors is the sum of the power rating of each. Here is one possible answer that assumes the resistors are rated at 1/4 watt and are connected in series. Power = Current ^ 2 x Resistance. The ^ means squared. Current = square root (Power / Resistance) Current = square root (0.25 / 50) = 0.0707 amps The total power of the three resistors in series is 0.25 x 3 = 0.75 watts Current = square root (0.75 / 150) = 0.0707 amps <-- Notice you get the same current as before. This must be true because the current flowing through a series circuit is the same in each component. Since Voltage = Current x Resistance Voltage = 0.0707 x 50 = 3.54 volts across one of the resistors OR Voltage = 0.0707 x 150 = 10.61 volts across the series combination. Here's another way to calculate the answer. Voltage = square root of (Power x Resistance) Voltage = square root (0.25 x 50) Voltage = 3.54 volts This is the maximum voltage across one of the resistors. If the three resistors are connected in series, the total resistance would be 150 ohms and the maximum voltage across the series combination would be 3.54 x 3 = 10.61 volts. If the resistors are connected in parallel, the equivalent resistance is 16.67 ohms. Since the voltage across parallel resistors is the same, the maximum voltage for three 1/4 watt resistors would be square root (0.75 x 16.67) = 3.54 volts. This is the same answer calculated for the resistors in series. The maximum current through each resistor is V / R = 3.54 / 50 = 0.0707 amps or the same current as the series combination. However, in this case, the total current flowing through the parallel combination is 0.0707 x 3 = 0.2121 amps and Power = I ^ 2 x R = .2121 ^ 2 x 16.67 = 0.75W. This proves that the powers add no matter if the resistors are in series or parallel. If the resistors are rated at 1/2 watt the maximum voltage across one resistor is 5 V and the maximum across the series combination is 15 V. The maximum current is 0.1 A.
What is total voltage in a series circuits?
In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.
What will happen to the other resistor if the number of resistor decreases?
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
What would be the total current and voltage dropped for each of the two resistors 7 and 9 ohms be if they're supply voltage is 230 volts?
Please specify whether the resistors are connected in series or in parallel.
What is voltage drop in parallel circuit?
First calculate your resistance for your parallel circuit using the reciprocal formula1/1/r1+1/r2 etc... Get that total and then add it to your resistance total of your series circuits. Divideyour applied voltage EA by Resistance Total RTthis gives you your current total or IT. Calculate your voltage drops by multiplying IT by your resistors in the series circuit. Subtract those voltage drops from your applied voltage EA and you now have your voltage drops for your parallel circuit, which all are equal to each other.
A 22 k and Ohm and 12 k and Ohm resistor are connected in series across a 68 V source how is the voltage divided?
If the resistors are in series the voltage can not be divided, as it has to pass first through one then the other. The amount of current that flows through a set of resistors in series will be the same at all points and the total resistance in the circuit must be equal to the sum of all the individual resistors added together. In other words the 22k and 12k Ohm resistors are the sames as a single 34k Ohm resistor.
