Want this question answered?
A hot air balloon.
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
The burners on a hot air balloon create hot air, which rises into the balloon and displaces the cooler air from the balloon. Then the hot air, being less dense, will lift the balloon as the cooler surrounding air sinks below it. Once the air cools, the balloon will lose its lift and settle back to the ground. The hot air is only slightly less dense, so it requires a lot of volume to lift the comparatively smaller mass of the balloon and gondola.
Because hot air rises and cold air sinks. So when they heat the air in the balloon it becomes less dense or less heavy and that makes it rise ad the volume becomes more. Because hot air rises and cold air sinks. So when they heat the air in the balloon it becomes less dense or less heavy and that makes it rise and the volume becomes more.
The answer is fairly simple, while some believe that a balloon bursts when near hot air because the balloon simple melts, it actually has to do with the pressure inside the balloon. When near hot air, the air inside the balloon expands slightly, causing a change in pressure, and causing the balloon to burst.
You change the volume or the weight of the balloon to raise it or lower it into air currents that are traveling where you want to go.
The air will expand, increasing the volume
The volume of air increases on its heating hence the balloon rises on heating
D: The hot air inside the balloon becomes less dense than the air outside the balloon.
A hot air balloon.
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
not at all
The burners on a hot air balloon create hot air, which rises into the balloon and displaces the cooler air from the balloon. Then the hot air, being less dense, will lift the balloon as the cooler surrounding air sinks below it. Once the air cools, the balloon will lose its lift and settle back to the ground. The hot air is only slightly less dense, so it requires a lot of volume to lift the comparatively smaller mass of the balloon and gondola.
as is, a rock, because density is mass over volume and a hot air balloon has a lesser/similar mass (stuff) but is spread out (volume) more than a rock.
Because hot air rises and cold air sinks. So when they heat the air in the balloon it becomes less dense or less heavy and that makes it rise ad the volume becomes more. Because hot air rises and cold air sinks. So when they heat the air in the balloon it becomes less dense or less heavy and that makes it rise and the volume becomes more.
The answer is fairly simple, while some believe that a balloon bursts when near hot air because the balloon simple melts, it actually has to do with the pressure inside the balloon. When near hot air, the air inside the balloon expands slightly, causing a change in pressure, and causing the balloon to burst.
This is the buoyancy force. Archimedes is credited with first formulating this into a mathematical principle: the buoyancy force of an object is equal to the weight of fluid it displaces. In the case of a hot air balloon, the "fluid" is the outside cool air and the balloon is displacing a volume of cool air equal to the volume of the inflated balloon. So you can say the buoyancy force F = V ρ g, where V is the volume of the inflated ballon, ρ is the outside air density, and g is gravity. A balloon can float because it is displacing this cool air with hot air which is less dense. The volume of hot air inside the balloon thus weighs less than the same volume of cold air outside the balloon. For a balloon to be float upwards, the buoyancy force has to be at least equal to the weight of the balloon (the balloon fabric, the gondola, the people, equipment and cargo, and the hot air inside). For example, for a balloon of 100,000 cubic foot volume (typical), with outside air at 20 deg C near sea level, the buoyancy force is about 7500 lbs. This force has to lift the gondola, people, equipment and of course the hot air inside the balloon, all of which have weight. By far the greatest percentage of that total weight is the heated air inside since there is so much of it.