For any wave, the product of (wavelength) x (frequency) is always the same number ...
the wave's speed.
So, as long as the speed stays the same, neither wavelength nor frequerncy
can change without the other one also changing.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
wavelength I will call lambda, frequency I will call f If f and lambda are the same then the velocities of the waves would be the same becuase v= lambda*f You know nothing about their phase angles or the amplitude of the waves though.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.
Speed is (Length/Time). Wavelength is (Length), and Frequency is (1/Time).Speed = (Wavelength)*(Frequency). With a constant speed, Wavelength and Frequency are inversely proportional to each other. So if one increases, the other decreases.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The speed of a wave is equal to the wavelength divided by the frequency (speed = wavelength/frequency). So if the frequency of the wave increases, the wavelength will decrease.
The wavelength would increase by the same proportion.
Electromagnetic waves have an associated frequency and wavelength. They are related by c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency. All electromagnetic waves travel at the speed of light. A change in frequency results in a change in wavelength (as required by the given equation). In short, yes. They're the same.
wavelength I will call lambda, frequency I will call f If f and lambda are the same then the velocities of the waves would be the same becuase v= lambda*f You know nothing about their phase angles or the amplitude of the waves though.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.
Speed is (Length/Time). Wavelength is (Length), and Frequency is (1/Time).Speed = (Wavelength)*(Frequency). With a constant speed, Wavelength and Frequency are inversely proportional to each other. So if one increases, the other decreases.