when dipole moment,torque and electric field all the three are perpendicular to each other.
direction-along the axis of dipole from -q to +q.
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
That would have to be when the dipole axis is perpendicular to the field.
The work done by you to turn the electric dipole end for end in a uniform electric field depends on the initial orientation of the dipole with respect to the field. If the dipole is initially oriented such that its positive and negative charges are parallel to the electric field, then no net work is done as the electric field does not do any work on the dipole as the electric field lines do not transfer any energy. On the other hand, if the dipole is initially oriented such that its positive and negative charges are perpendicular to the electric field, then work is done by you to turn the dipole as the electric field exerts a force on the charges in the dipole in opposite directions, causing them to move in opposite directions. As a result, you have to do work to move the charges and turn the dipole.
expression for the electric field in the perpendicular bisector plane of a dipole
Zero Dipole would set itself such that dipole moment vector is along the electric field vector
So interesting query! As we keep the dipole with its dipole moment along the direction of the electric field then it will be in stable equilibrium. IF we keep the same dipole inverted ie its dipole moment opposite to the external field then the dipole will be in unstable equilibrium.
direction-along the axis of dipole from -q to +q.
Because opposite charges attract. The negative end of the dipole moment is trying to get to the positive end of the field, and the positive end of the dipole is trying to get to the negative end of the field.
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
That would have to be when the dipole axis is perpendicular to the field.
yes, there is a NET field .electric dipole experiences a net field .(not in uniform E.Field)
The work done by you to turn the electric dipole end for end in a uniform electric field depends on the initial orientation of the dipole with respect to the field. If the dipole is initially oriented such that its positive and negative charges are parallel to the electric field, then no net work is done as the electric field does not do any work on the dipole as the electric field lines do not transfer any energy. On the other hand, if the dipole is initially oriented such that its positive and negative charges are perpendicular to the electric field, then work is done by you to turn the dipole as the electric field exerts a force on the charges in the dipole in opposite directions, causing them to move in opposite directions. As a result, you have to do work to move the charges and turn the dipole.
Since there is charge separation in a polar covalent bond, there is also resultant electric field from partial positive charge to partial negative charge.hence due to electric field in one direction and also magnitude of equal and opposite charge.....it is a vector.
expression for the electric field in the perpendicular bisector plane of a dipole
It experiences a torque but no force. As the dipole is placed at an angle to the direction of a uniform electric field it experiences two opposite and equal forces which are not along the same line. This develops a torque which aligns the dipole along the field. The dipole does not experience any force as the two forces cancel each other.
uses of dipole materials