As a simple rule of thumb, sound travels at 1 mile every 5 seconds.
So, in 4 seconds, it has travelled 4/5 of a mile.
To be exact, it depends on the density of the air, which is determined by the altitude above sea level, the temperature of the air, and the relative humidty of the air (also know as the density altitude, a term used by pilots).
I think that you left out some information but 330 m/s for 3 seconds would mean the thunder and the lightening were both at the same place when they were 990 meters away from you. The general concept that is missing in the question as you stated it is that you see lightning instantly but the thunder will show up 330 meters later per second.
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The transit time for the light is (D / 300,000,000) meters
The transit time for the sound is (D / 340) meters
The difference in transit times is D (1/340 - 1/300,000,000) = 6 seconds
D/340 - D/300,000,000 = 6
The first term is almost 890,000 times larger than the second term, so I'll ignore the second term.
D/340 = 6
D = 6 x 340 = 2,040 meters = 2.04 kilometers.
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How long did it take the flash of the lightning to reach me ?
2.04 / 300,000 = 6.8 microseconds, against the observed 6 seconds. So it was OK to ignore the transit time of the light.
The speed of sound is 768 mph.
7.4 sec x 768 mile/hr x 1 hr / 60 min x 1 min / 60 sec = 1.6 mile
you have to use a formula D=VT
Hope that helps!!
about 20 seconds away, aka right on you be careful
(1,029 miles away) A+
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 meters high.
Velocity = Frequency * Wavelength Frequency = Velocity / Wavelength Frequency = 340 m/s / 15 m Frequency ~ 22.67 1/s Frequency = 22.67 Hz
Speed of sound is c ≈ 331 + 0.6 × T T = temperature in °C. Speed of sound at 30°C is c ≈ 331 + 0.6 × 30 = 349 m/s.
For a wavelengt lambda in air with the speed of sound of c = 340 meters per second the frequency f: f = c / lambda. A wavelength of 5 meters equals a frequency of 68 Hz. A wavelength of 0.2 meters equals a frequency of 1700 Hz. There is a useful calculator for converting wavelength to frequency and vice versa. Scroll down to related links and look at "Acoustic waves or sound waves in air".
It is different in different conditions. Generally it has 340ms-1 as the speed.
It was the same speed. It generally travel with 340ms-1 speed.
This is a low temperature. It travels in less than 340ms-1.
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 meters high.
Velocity = Frequency * Wavelength Frequency = Velocity / Wavelength Frequency = 340 m/s / 15 m Frequency ~ 22.67 1/s Frequency = 22.67 Hz
v = fλ V/f = λ (wavelength) V = 340ms-1 340/f = λ In short you need to know the frequency of the particular sound wave to work out it's wavelength. once you know that you plug it into the above equation and you will get the wavelength of the wave.
At 14 °C the speed of sound is 339.8 m/s. Here is an easy calculator to di that: http://www.sengpielaudio.com/calculator-speedsound.htm Cheers ebs
That will not only depend on the temperature, but also on the exact composition of the air (such as, whether it is dry or humid), and possibly on the pressure. The typical speed of sound at 20 degrees C is approximately 343 meters/second.
Speed of sound is c ≈ 331 + 0.6 × T T = temperature in °C. Speed of sound at 30°C is c ≈ 331 + 0.6 × 30 = 349 m/s.
For a wavelengt lambda in air with the speed of sound of c = 340 meters per second the frequency f: f = c / lambda. A wavelength of 5 meters equals a frequency of 68 Hz. A wavelength of 0.2 meters equals a frequency of 1700 Hz. There is a useful calculator for converting wavelength to frequency and vice versa. Scroll down to related links and look at "Acoustic waves or sound waves in air".
The speed of sound is dependent on the temperature and not on the air pressure. At 20 degrees Celsius or 68 degrees Fahrenheit the speed of sound is 343 m/s or 1236.3 km/h or 1126.7 ft/s or 667.1 knots.Scroll down to related links and look at "Speed of sound - temperature matters, not air pressure".At room temperature (20°C, 68° F) the speed of sound is 343 meters per second, 767 miles per hour, or 0.213 miles per second.Sound waves must have matter and/or molecules to travel. Where there is no matter, such as in outer space, sound cannot travel.At room temperature (20°C, 68° F) the speed of sound is 343 meters per second, 767 miles per hour, or 0.213 miles per second.Sound waves must have matter and/or molecules to travel. Where there is no matter, such as in outer space, sound cannot travel.At 20 degrees Celsius the sound travels in air 343.4 meters per second. That means in 1 second the sound travels 343.3 meters. In 2.912 milliseconds the sound travels 1 meter.Well it is really dependent on the temperature of the air, but in this case we will assume the standard temperature ( 20 degrees C) it travels at 343 meters per second.Through air, sound waves travel at 343 m/s
Assuming that both notes are in the range of C4 (middle C) and C5, G has a frequency of 392Hz, and A has a frequency of 440Hz. Assuming that both sound waves are travelling through air, through which sound travels at 340ms-1, then the wavelengths for G and A can be found to be 0.87m and 0.77m, respectively.An easier way to assess a change in wavelength would be to look at the equation v=fλ, where v is the speed of sound, f is the frequency of the note, and λ is the wavelength of the note. A higher pitch note means a higher frequency, and since the speed of sound is constant, then if the pitch is increased the wavelength must compensate by decreasing.Simply put, higher pitch means smaller wavelength.