696 meters
You kicked the rock with an initial velocity of 3.4 m/s.
4 m/s
0.82 metres.
When given a constant acceleration, just multiply it by time, t, to detemine the final velocity. If the initial velocity was zero (as is the case when you drop something), then the average velocity is half the terminal velocity.
The plane's velocity at 10 seconds will be 150 meters per second or 335.54 mph
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
You kicked the rock with an initial velocity of 3.4 m/s.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
4 m/s
the answer is 24-9 m/sec. yuor welcome
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration
0.82 metres.
0.82 metres.