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0.82 metres.

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Q: A girl throws a tennis ball upward with an initial velocity of 4 meters per second . What is the maximum displacement of the ball?
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A girl throws a tennis ball upward with an initial velocity of 4 meters per second. What is the maximum displacement of the ball?

0.82 metres.


If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?

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When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?

'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters


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The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.