The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
initial velocity of the kick = 28.06 m/s
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?
0.82 metres.
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
initial velocity of the kick = 28.06 m/s
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?
V=at. If you figure out the velocity of an object accelerating at 1 g for a year, you will get a velocity that is almost the speed of light (non-relativistically of course).
0.82 metres.
0.82 metres.
Without air, the speed of a falling object keeps increasing, and never reaches a maximum. The only thing that causes it to reach a maximum and stop increasing is air resistance. The effects of air resistance depend on the size, shape, and composition of the object, and the calculation of the "terminal velocity" in advance is very complex.
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum