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What is the maximum height a sphere shot from cannon can reach?
That depends on basically three things: the angle at which the cannon is fired, the velocity of the projectile, and the acceleration of gravity. The maximum range of the cannon is achieved with a firing angle of 45 degrees to the horizontal. But the maximum height is achieved when the firing angle is 90 degrees to the horizontal, that is, when the cannon is pointing straight up into the air. (Which can be very dangerous to the artillery personnel firing the guns!) So, if we assume that the cannon is on Earth, not some other planet, and fired straight up into the air, can we determine how high the cannonball will go? Yes, if we know the velocity of the cannonball as it leaves the end of the cannon's tube. Once the cannonball leaves the end of the tube, it begins to slow down because of the acceleration of gravity. We can use the energy equations to calculate the maximum height of the cannonball. We know that kinetic energy is defined by the equation Ek = mv2/2. We also know that potential energy (due to altitude) is defined by the equation Ep = mgh. Equating the two, we get mv2/2 = mgh. Rearranging the terms to solve for h, we get: h = v2/2g. (Note that g = 9.8 m/s2 = 32.2 ft/s2.) So, let's say the cannon has a muzzle velocity of 1000 meters per second. The cannonball, therefore, has an initial velocity of 1000 m/s before it starts to slow down. Plugging 1000 into the equation above and solving for h, we calculate the theoretical maximum height as 51,020 meters. In practice, however, the cannonball will not achieve anywhere near that height because of air resistance, which has a tremendous effect at such high speeds.
How do you calculate maximum earth fault current?
transformer max earth fault current
How do you calculate full load for 500amp welding machine?
You need the input voltage and maximum input current specs found on the name plate.
How do you get minimum and maximum value of resistor?
The minimum and maximum possible value is defined by the tolerance. To calculate the range of the resistor, simply add or remove the amount of the tolerance. For example, a 100Kohm resistor with 5% tolerance can range from 95Kohm through until 105Kohm. The lower the tolerance, the more accurate the resistor is.
What is the maximum seats in lok sabha?
lok sabha has 320 seats as maximum
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
How can one determine the maximum height reached by an object launched with a given initial velocity?
To determine the maximum height reached by an object launched with a given initial velocity, you can use the formula for projectile motion. The maximum height is reached when the vertical velocity of the object becomes zero. This can be calculated using the equation: Maximum height (initial velocity squared) / (2 acceleration due to gravity) By plugging in the values of the initial velocity and the acceleration due to gravity (which is approximately 9.81 m/s2 on Earth), you can find the maximum height reached by the object.
What is the initial arclength of a pendulum when you know the length and mass and max velocity and initial height of the pendulum?
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
What is the initial velocity of a bullet fired verticaly upward from a gun and reaches a height of 7000 ft?
The initial velocity of the bullet can be obtained by using the kinematic equation for projectile motion. Assuming we neglect air resistance, the initial velocity of the bullet fired vertically upward from a gun can be calculated by setting the final velocity as 0 when it reaches the maximum height of 7000 ft. Using the equation v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity, a is the acceleration due to gravity, and s is the total displacement. Solve for u to find the initial velocity of the bullet.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
What is the method to calculate the maximum transverse velocity of the string at this point?
To calculate the maximum transverse velocity of the string at a specific point, you can use the formula v A, where v is the maximum transverse velocity, A is the amplitude of the wave, and is the angular frequency of the wave.
A ball is shot out of a cannon with initial velocity 30ms at 30 degree above the horizontal. How long is ball in the air How far away from the cannon does the ball hit What the max height by ball?
The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
When is the speed of a fluid maximum in a venturi meter?
from the continuity equation A1v1 = A2v2 according to the continuity equation as the area decreases the velocity of the flow of the liquid increases and hence maximum velocity can be obtained at its throat
A boy kicks a ball vertically upwards with an initial velocity of 12m/s. Calculate the time taken by the ball to reach the maximum hight and the maximum, height reached by the ball?
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
How do you calculate maximum velocity of a falling object?
Without air, the speed of a falling object keeps increasing, and never reaches a maximum. The only thing that causes it to reach a maximum and stop increasing is air resistance. The effects of air resistance depend on the size, shape, and composition of the object, and the calculation of the "terminal velocity" in advance is very complex.
1 If you toss a ball upward with a certain velocity it falls freely and reaches a maximum height h What maximum height does the ball reach if you throw it upward with double the initial velocity?
Multiply the height by 4. The equation to use is h=-16t2 + v0t + h0. Use whatever values you want for v0 and h0, and find the vertex of the parabola. Then double your value of v0, and find the vertex of your new parabola. It will be 4 times as high every time. By the way, to find the vertex, plug in v0/32 for t. Then solve for h.
