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The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
What else can I help you with?
Why does 45 degrees give maximum range?
When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
A ball is thrown upwards with a velocity of 10m's how high does it go?
You can solve this using kinematics: Since you have height: 20m and acceleration being 10 for this question you can easily find the final velocity The initial velocity MUST be 0 since you are dropping it. with that being said Use: V^2= Vi^2 + 2ad
Why does a 45 degree throw go the furthest?
A 45-degree throw maximizes the horizontal distance traveled by balancing the vertical and horizontal components of the projectile's velocity. At this angle, the horizontal component is at its maximum, maximizing the range the object can travel before hitting the ground. Any angle higher or lower will result in a shorter distance traveled.
At what angle from a horizontal should a weapon be fired to achieve minimum distance traveled by the projectile?
The weapon should be fired at a 45-degree angle from the horizontal to achieve the minimum distance traveled by the projectile. This angle maximizes the range (horizontal distance) of the projectile by balancing the vertical and horizontal components of its velocity. At any other angle, the total distance traveled would be greater.
Why does a projectile thrown at 45 degree travel the most distance?
A projectile thrown at a 45-degree angle achieves the maximum horizontal distance due to the optimal balance between vertical and horizontal velocity components. At this angle, the initial velocity is divided equally between the upward and forward directions, maximizing the time the projectile spends in the air while also ensuring significant horizontal displacement. Additionally, this angle minimizes the effects of gravitational pull on the projectile's trajectory, allowing it to cover the greatest horizontal distance before landing.
Water is projected from two rubber pipes at the same speed-from one at an angle of 30 and from the other at 60why are the ranges equal?
w2hen the angle of projection is larger than 45 degree the height attained will be more but the range is again less.in this case angle is 30 degree which is less than 45 degree and 60 degree angle is greater than angle of 45 degree which have less range and is equal to range of 30 degree .so ranges are equal.
A stone is projected with a velocity of 58.8 ms at an angle of 30 degree from horizontal find the Time of flight maximum height and horizontal range?
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
Why does 45 degrees give maximum range?
When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
What is the meaning of horizontal position?
Horizontal position is strate 90 degree
How many feet are in a degree?
4
How fast was a civil war cannon ball?
A cannon ball traveled at speeds up to and or exceeding 100 miles per hour this depended on how well the cannon was packed how much powder was charged and the degree the cannon barrel was angled many soldiers packed two balls connected by a large chain this increased the effectiveness of the cannon others where loaded with many smaller balls like buckshot in a shotgun.
A ball is thrown upwards with a velocity of 10m's how high does it go?
You can solve this using kinematics: Since you have height: 20m and acceleration being 10 for this question you can easily find the final velocity The initial velocity MUST be 0 since you are dropping it. with that being said Use: V^2= Vi^2 + 2ad
A 6 kg block is pushed 8 m up a rough degree inclined plane by a horizontal force of 75 N if the initial speed is 2 ms and kinetic friction of 25N opposes the motion what is the initial kinetic en?
In this question, we would use the equation K = 1/2mv^2 we know: mass (m) = 6 kg initial velocity (v) = 2 m/s therefore, K = 1/2(6)(2^2) K= 12 Joules (J)
Why does a 45 degree throw go the furthest?
A 45-degree throw maximizes the horizontal distance traveled by balancing the vertical and horizontal components of the projectile's velocity. At this angle, the horizontal component is at its maximum, maximizing the range the object can travel before hitting the ground. Any angle higher or lower will result in a shorter distance traveled.
How do you make an angle with horizontal direction?
90 degree
