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How do you calculate the gain of Kinetic Energy?
The gain in kinetic energy can be calculated using the equation: ΔKE = KE_final - KE_initial, where KE is the kinetic energy. Simply subtract the initial kinetic energy from the final kinetic energy to determine the gain.
A block of mass 300 g is sliding on a rough surface with an initial speed of 1.4 ms It comes to a rest after a time of 0.80 s What is the coefficient of kinetic friction?
We can easily calculate that deceleration of block is a = v / t = 1.4 / 0.8 = 1.75 m/s2. The only force acting in the plane of movement may be Ft due to friction. Formula for Ft is Ft = Q * f, where Q is weight and f is a coefficient of friction. Q is: Q = m * g Ft has also to equal Ft = m * a, so: m * a = m * g * f a = g * f f = a / g f = v / ( t * g) For given data, f will be f = 1.4 / ( 0.8 * 9.81) = 0.178
An object glides on a horizontal tabletop with a coefficient of kinetic friction of 0.3 If it comes to rest after 1.3 seconds what was its initial velocity?
Correct and easier way: Kinetic friction is just a part of magnitude of forces affecting an object, so it can be multiplied by g(9.81) to get the total acceleration essentially. Coefficient(.3)=F(friction)/F(normal) So multiply .3 by g(9.81) to get 2.943 -2.943 is the acceleration of the object, as it's slowing down) So then, simply multiply by time (1.3) to get a Vi of 3.8259 Ffriction = -0.3 * m * g = m * a a = -0.3 * g So if we integrate over time: v(t) = -0.3 * g * t + v(0) We know that v(t=1.3) = 0. So we can place it in the equation. v(t=1.3) = 0 = -0.3 * g * 1.3 + v(0) v(t=0) = 0.3*1.3*g = 0.39 * g = 0.507 meters per second
What is the primary factor in decreaseing the kinetic energy of an object?
The primary factor in decreasing the kinetic energy of an object is applying an external force in the direction opposite to its motion, which results in negative work being done on the object. This reduces its speed and kinetic energy.
After rolling halfway down an incline a marble's kinetic energy is?
The marble's kinetic energy is halfway between its initial and final energies. This is because kinetic energy is proportional to the square of the velocity, and velocity would have increased as the marble rolled down the incline, reaching its maximum velocity at the bottom.
What is the coefficient of kinetic friction between the 13.0kg wooden crate and the horizontal force of 31N of the floor?
The coefficient of kinetic friction can be calculated using the formula: coefficient of kinetic friction = force of kinetic friction / normal force. The force of kinetic friction can be found using the formula: force of kinetic friction = coefficient of kinetic friction * normal force. Given the force of 31N and normal force equal to the weight of the crate (mg), you can calculate the coefficient of kinetic friction.
What is the difference between static friction and kinetic friction?
Static friction is the force that resists the initial movement of an object at rest, while kinetic friction is the force that resists the movement of an object already in motion.
How does the coefficient of kinetic friction vary with the the area of contact between the block and he horizontal?
The coefficient of kinetic friction remains constant regardless of the area of contact between the block and the horizontal surface. It is a property of the materials in contact and does not depend on the surface area.
Which form of friction is harder to overcome static or kinetic?
Static friction is generally harder to overcome compared to kinetic friction. This is because static friction opposes the initial motion of an object and requires more force to initiate movement, while kinetic friction opposes the motion of an object already in motion.
What friction is harder to overcome?
Static friction is generally harder to overcome compared to kinetic friction because static friction is the force that resists the initial motion of an object. Once an object is in motion, the friction force is reduced to the kinetic friction force, which is usually lower.
Which has a maximum value kinetic friction or static friction?
The maximum value of static friction is typically greater than the maximum value of kinetic friction. Static friction is the force required to overcome the initial resistance of an object at rest, while kinetic friction is the force required to keep an object in motion.
A 2.7-kg box is released on a horizontal surface with an initial speed of 2.9 ms It moves on the surface with a deceleration of 0.27 ms2 Calculate the kinetic friction force on the box?
The force of kinetic friction can be calculated using the formula: force of kinetic friction = mass * acceleration. The acceleration in this case is the deceleration, so the force of kinetic friction = 2.7 kg * 0.27 m/s^2. Therefore, the kinetic friction force on the box is 0.729 N.
What is the example of static friction?
put ur hand on the table. move hand from rest horizontally on table. initial friction is static, once moving its called kinetic friction
What kind of friction requires more force?
Static friction generally requires more force to overcome compared to kinetic friction. Static friction occurs when two surfaces are at rest relative to each other, while kinetic friction occurs when the two surfaces are in motion. This is because static friction opposes the initial force applied to move an object, while kinetic friction only opposes the ongoing motion.
Why coefficient of static friction is larger than kinetic friction?
The coefficient of static friction is typically larger than the coefficient of kinetic friction because it represents the maximum force required to start an object in motion, overcoming the initial static friction. Once the object is in motion, the kinetic friction is usually less because the surfaces are already moving relative to each other, resulting in lower resistance.
Is The force needed to overcome static friction usually less than that needed to overcome kinetic friction.?
True -It's "False"!
A 5.0 kg block of ice at -1.5C slides on a horizontal surface with a coefficient of kinetic friction equal to 0.058 The initial speed of the block is 6.0 ms and its final speed is 5.5 ms.?
Assuming that all the energy dissipated by kinetic friction goes into melting a small mass m of the ice, and that the rest of the ice block remains at -1.5°C, determine the value of m.
