A ball is thrown upwards with a velocity of 10m's how high does it go?

Answer 1

You can solve this using kinematics: Since you have height: 20m

and acceleration being 10 for this question

you can easily find the final velocity The initial velocity MUST be 0 since you are dropping it.

with that being said Use: V^2= Vi^2 + 2ad

Answer 2

initial velocity is zero.

u=0

acceleration=a=g=9.8 m/s^2

distance=s=10m

v^2 - u^2=2as (Newton's law of motion)

v^2=2*g*10

v^2=196

v=14m/s. (ans)

Answer 3

Since you said "horizontally", the force of gravity in the direction of initial movement will be zero. That means that gravity will not be acting to change the horizontal component of the balls velocity. However, there will be some degree of wind resistance that will slighly slow the ball over time. So....depending on how long it takes the ball to hit the ground will determine the final horizontal speed. For any practical situation, the horizontal speed on impact will be nearly 20 meters per second.

Answer 4

The maximum height the ball reaches can be calculated using the kinematic equation: h = (v^2)/(2g) where v is the initial velocity (10 m/s) and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, the height the ball reaches is approximately 5.1 meters.

Answer 5

5.1 meters