You can solve this using kinematics: Since you have height: 20m
and acceleration being 10 for this question
you can easily find the final velocity The initial velocity MUST be 0 since you are dropping it.
with that being said Use: V^2= Vi^2 + 2ad
initial velocity is zero.
u=0
acceleration=a=g=9.8 m/s^2
distance=s=10m
v^2 - u^2=2as (Newton's law of motion)
v^2=2*g*10
v^2=196
v=14m/s. (ans)
Since you said "horizontally", the force of gravity in the direction of initial movement will be zero. That means that gravity will not be acting to change the horizontal component of the balls velocity. However, there will be some degree of wind resistance that will slighly slow the ball over time. So....depending on how long it takes the ball to hit the ground will determine the final horizontal speed. For any practical situation, the horizontal speed on impact will be nearly 20 meters per second.
5.1 meters
when a ball is thrown upwards velocity increases but acceleration decreases hence making it anti parallel to each other
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
In that case, the velocity is zero.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
It is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
when a ball is thrown upwards velocity increases but acceleration decreases hence making it anti parallel to each other
The ball goes up 5.1 meters.
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
In that case, the velocity is zero.
The ball returns to the ground with increasing velocity due to acceleration due to gravity. At a point (terminal velocity) the ball maintains a constant velocity (due to air resistance) This occurs when the weight of the ball is equal to the viscous drag of the air (air resistance) and upthrust (weight of air displaced).
There's no such thing as "time of the downward velocity", but I think I get the sense of your question. If the effects of air resistance can be disregarded, then any object thrown upwards spends half of its time rising, and the identical amount of time falling back to the height of your hand when you let it go.
A ball thrown down. The thrown ball will have a greater initial velocity and since they experience the same force of gravity, it will always be faster (until they both reach terminal velocity).
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
It is converted to the ball's velocity or it is known as its velocity because displacement changes with time is known as velocity.
As velocity never exceeds the velocity of light.... so i hope a man running with the velocity of light will not be able to throw a ball with any velocity.......... we may get the maximum n minimum velocity with which that can be thrown mathematically that we may get it to be zero................
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
In the case of constant velocity (or speed), velocity = distance / time.