The only constant when a ball is thrown upward is the acceleration due to gravity acting in the opposite direction to the velocity of the ball. Other factors, such as air resistance and the initial velocity of the ball, may change as the ball moves.
The velocity of the ball is 16 feet/sec when it is thrown upward.
No, the horizontal component of velocity remains constant for an object in projectile motion as long as no external forces act horizontally on the object. In the case of a ball thrown upward, the horizontal component of velocity remains unchanged unless affected by air resistance or other external forces.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
The initial velocity of the ball thrown upward at 16 ft per second is 16 ft/s.
The velocity of a ball thrown upward at 16 ft/sec would be 16 ft/sec when it leaves the hand, but it will decrease due to gravity as it moves upward.
because there if speed is constant than ball never come back to earth hence speed of ball is not constant
The velocity of the ball is 16 feet/sec when it is thrown upward.
No, the horizontal component of velocity remains constant for an object in projectile motion as long as no external forces act horizontally on the object. In the case of a ball thrown upward, the horizontal component of velocity remains unchanged unless affected by air resistance or other external forces.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
The initial velocity of the ball thrown upward at 16 ft per second is 16 ft/s.
The velocity of a ball thrown upward at 16 ft/sec would be 16 ft/sec when it leaves the hand, but it will decrease due to gravity as it moves upward.
A ball thrown upward is not considered a free falling body because it initially moves against gravity. Free falling bodies accelerate downward due to gravity alone, while a ball thrown upward has an initial velocity in the opposite direction.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
Slower than the initial speed it was thrown upward with due to air resistance causing the ball to lose speed as it travels through the air. The force of air resistance acts against the direction of motion and slows down the ball.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.