The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The boy throws a stone vertically upward with an initial velocity of 6.0 m/s, meaning the stone is moving against gravity. It will reach a maximum height and then fall back down due to gravity. The stone will eventually return to the ground after reaching its highest point.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
The boy throws a stone vertically upward with an initial velocity of 6.0 m/s, meaning the stone is moving against gravity. It will reach a maximum height and then fall back down due to gravity. The stone will eventually return to the ground after reaching its highest point.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
The initial velocity of the bullet can be obtained by using the kinematic equation for projectile motion. Assuming we neglect air resistance, the initial velocity of the bullet fired vertically upward from a gun can be calculated by setting the final velocity as 0 when it reaches the maximum height of 7000 ft. Using the equation v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity, a is the acceleration due to gravity, and s is the total displacement. Solve for u to find the initial velocity of the bullet.
To determine the maximum height reached by an object launched with a given initial velocity, you can use the formula for projectile motion. The maximum height is reached when the vertical velocity of the object becomes zero. This can be calculated using the equation: Maximum height (initial velocity squared) / (2 acceleration due to gravity) By plugging in the values of the initial velocity and the acceleration due to gravity (which is approximately 9.81 m/s2 on Earth), you can find the maximum height reached by the object.
To calculate the maximum transverse velocity of the string at a specific point, you can use the formula v A, where v is the maximum transverse velocity, A is the amplitude of the wave, and is the angular frequency of the wave.
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
We suspect that you're also given a line on the graph. If so, then the initial speed is the slope of the line at the initial position. To get the real slope of the line, you need to know the scales of the axes. If the scales aren't the same, then the real slope of the line isn't what it looks like, and has to be calculated by measuring its progress along both axes just after the initial position.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?