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Xf= Xi + Vxi(t) + (.5)(Ax)(t)2 where:

Xf is the final position

Xi is initial position

Vxi is initial velocity

Ax is average acceleration

t is time

Xi and Vxi will both be zero since the initial velocity and position are both zero.

Xf = (0) + (0) + (.5)(9.8m/s2)(20)2

Xf = 1960 meters

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