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you have 0.1 Moles of sulfuric acid with 0.2 moles of H ions thus requiring 0.2 moles of NaOH - molecular weight = 40 so 40 x 0.2 = 8g NaOH

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Q: How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
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Related questions

How many NaOH required to neutralize complitly4.9 gms of H2SO4?

Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================


How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?

Balanced equation. H2SO4 + 2NaOH >> Na2SO4 + 2H2O 10 grams NaOH (1mol NaOH/39.998g )(1mol H2SO4/2mol NaOH )(98.086g H2SO4/1molH2SO4 ) = 12.26 grams of H2SO4


How many grams of NaOH and H2SO4 are needed to produce 200 g Na2SO4?

112,64 g of NaOH and 138,1 g of H2SO4


What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?

14.1 mL is required to titrate 10.00 ml of 0.526 M H2SO4.


A 25.00ml sample of h2so4 requires 22.65 ml of the 0.550m naoh for its titration what was the concentration of sulfuric acid?

(25.00ml H2SO4)(H2SO4 M) = (22.65ml NaOH)(0.550M) = 0.4983M H2SO4


How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?

Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================


What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?

40 grams, this is the 1M NaOH standard laboratory solution.


When NaOH and H2so4 react what color does it make?

Both NaOH and H2SO4 have no colour, even not after complete reaction (Na2SO4 and H2O are also colourless)


Which acid is stronger vinegar H2So4 NaOH?

Vinegar


What mass of NaOH is required to make up 100 mL of a 0.5000 M solution?

Two parts.Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters )0.5000 M NaOH = X moles/0.1 L= 0.05 moles NaOH--------------------------------now,0.05 moles NaOH (39.998 grams/1 mole NaOH)= 1.99 grams NaOH required====================( could call it 2.00 grams )


How many moles of NaOH are in 8 g of NaOH?

8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH


Which indicator is used in titration of naoh and h2so4?

Methyl orange