momentum is the product of mass and velocity. p for momentum m for mass and v for velocity. (p=m*v)
P = I^2R R = p(L/A) P = power (watts) I = current(Amps) R = resistance(ohms) L = length of wire(m) A = cross sectional area of wire(m^2)
There are 2 "m"s and 1 "p" in the phrase "How many m p's are there."
5=p. of the m.
iS 645 a m p m
nx - m = p so x = (m+p)/n
in the equation p=m x v, the p represents
<p>MCMLXXVI</p> <p>or M + (CM) + (LXX) + VI</p> <p>or M + (M - C) + L + X + X + V + I</p> <p>or 1000 + 900 + 70 + 6</p> <p>or 1976</p>
B
bmsk
I'm on it . . .p = 2 / (m + q)Multiply each side by (m + q) :p (m + q) = 2Divide each side by 'p' :m + q = 2/pSubtract 'm' from each side:q = 2/p - m
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.