A thryroid BX may be done if nodules are found on the thyroid gland. The procedure is done by inserting a special type of needle into the thyroid and a small piece is then removed and sent to be tested.
use inform of drug about thyroid secritions
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Is a hormone secreted bx thyroid gland important in maintaing calcium and phosphate balance of the body,normal development of neurons,maintaining metabolic rate,important in growth of infants.
Suggesting Thyronormalcy means that there are no disorders in the thyroid test done
This is done by extracting cells from the thyroid using a very fine needle. It is usually done under local anaesthetic and then the cells are sent to a cytopathologist to be analysed.
There are several tests done for thyroid function. They require different tubes.
There are several tests done for thyroid function. They require different tubes.
this is a test for your thyroid and its done with a blood draw
There is a chance that when surgery was done to remove the thyroid, the cancer may have spread already. If the cancer hadn't spread before surgery was done, there should be no spread.
Bronx
A thyroid uptake scan wouldn't normally be needed unless it is suspected that thyroid tissue was missed during surgery (sometimes thyroid tissue can be found in other areas of the body), or the reason for the surgery was cancer and the removal of all the tissue is vital.
.code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x mov bx,y ;bx=y cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp