A man has type A blood and his wife has type B a physician types the blood of their four children and is amazed to find one of each of the blood type among them How could this happen?

Answer 1

The definition of heterozygous A means the parent has an A gene and an "i" or basically an "O" gene.

The heterozygous B parent has a B gene and an "i".

So the genotypes are Ai and Bi. If you set up a Punnet square, the four possible gene selections are AB, Ai, Bi, or ii. If the child has "ii" then it is said the child has O blood. The AB child has AB blood, the Ai child has A blood, and the Bi child has B blood.

(Remember this scenario does not take into account the negative and positive part of blood types. Such as O- and O+ both have O blood but one is O negative and the second is O positive. Your question didn't ask this but I have seen many "trick" questions in Biology classes where the negative and positive blood types are part of the answer.)

Hope this helps! :)

Answer 2

Just use a "Punnet Square"! A is dominate in the man and B is dominate in the woman, that means that they each have a gene that has a different and less dominate bloodtype, which can be passe on to their children.

Answer 3

Because O is recessive and A and B are dominant, both parents could be carrying an O form of the gene without it being apparent. If their baby inherited the O from each of them, the baby would have an O blood type.

Answer 4

If the woman had B-B blood, their children would be: 50% AB, 50% BB. In other words, 50% AB and 50% B.

If the woman had B-i blood, their children would be: 25% AB, 25% Ai, 25% Bi, and 25% BB blood type. In other words: 50% B, 25%A and 25%AB.

Answer 5

Both of the parents carried a recessive allele for the trait for having type O blood.

Answer 6

simple hes a type b