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How is memory address used to access an abstract data type that is larger than 1 byte?
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How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
How many memory address does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many address lines can access a 16MB memory?
for 16 MB memory has 24 address lines
How can you upgrade your computer if it does not have enough random-access memory?
You add more memory, or you replace the memory with larger modules.
What is a memory pointer?
A pointer is a variable that stores a memory address and that allows indirect access to the object or value stored at that address.
Minimum number of address lines needed to access a physical memory of 1GB?
You need 30 address lines to access 1G of memory. 230 = 1,073,741,824. log2 (1,073,741,824) = 30.
How many memory addresses does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
What is the meaning of memory mapped bus?
Memory mapped buses helps in the extension of the address of the physical ram through which the devices can access the address
How many memory locations can 14 address bits access?
16384
Maximum memory address space that the processor can access directly if it is connected to a 16-bit memory?
Max. memory address space= 216 X 2 bytes = 128 Kbytes
What is the difference between sam and ram?
In RAM ,the access time is the same for any memory location.Semi-conductor IC chips and magnetic disks are random access memory.In SAM a particular memory word is accessed from the memory by going through all address locations until the desired address is found.Magnetic tapes are sequential access memory.
What is the maximum memory address space that the processor can access directly if it is connected to a 16 bit memory considering a hypothetical microprocessor generating a 16-bit address?
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
