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Q: How is the length of a lever related to the moment of a force?
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The product of force and lever-arm distance in producing rotation is?

In a lever, the product of effort and effort arm is called Moment of effort and product of load and load arm is called Moment of load. In general case, as asked in the question, "The Product of force and lever-arm distance is called Moment of Force"the Moment of Force isn't correct its {Torque}


Why a door can be closed or opened easily by applying force at any point away from the pivot?

When a force rotates something about an axis is called moment of force or torque. Torque = Length of lever arm x Force From this equation you can see that as the length of the lever arm increases, the torque increases. That is why if you try to push or open the door near the pivot, you will need more force to rotate it. Hope this helps.


Part of a lever on which effort force is applied?

Third class.


What is lever arm ratio?

Divide the length of the force arm by the length of the resistance arm.


Is 150 pound-feet of torque much different from 100 pound-feet?

for a given lever length the force is (150 / 100) times greater torque = force (pounds) * lever length (feet)


What is Turning effect of force?

rotator


Can you determine the input force by knowing the input and output arm length and the output force of a lever?

Yes


What is the unit of torque?

the unit of torque is NM.Torque has dimensions of force times distance. Official SI literature suggests using the unit newton metre (N·m) or the unit joule per radian.[8] The unit newton metre is properly denoted N·m or N m.Torque, moment or moment of force is the tendency of a force to rotate an object about an axis.The magnitude of torque depends on three quantities: the force applied, the length of the lever arm[2] connecting the axis to the point of force application, and the angle between the force vector and the lever arm. In symbols:whereτ is the torque vector and τ is the magnitude of the torque,r is the displacement vector (a vector from the point from which torque is measured to the point where force is applied), and r is the length (or magnitude) of the lever arm vector,F is the force vector, and F is the magnitude of the force,× denotes the cross product,θ is the angle between the force vector and the lever arm vector.


What is the relationship between distance ratio and mechanical advantage?

The mechanical advantage of a lever is the ratio of the length of the lever on the applied force side of the fulcrum to the length of the lever on the resistance force side of the fulcrum. There are three types of levers - class 1, class 2, and class 3.


Why is it hard to push the fulcrum part of a lever?

because the 'moment' acting on the lever is force multiplied by distance, thus the greater the distance from the pivot/fulcrum the greater the moment i.e. it's easier to push.


When calculating the mechanical advantage of a lever what two pieces of information are needed?

You need to know the length of the lever and the location of the fulcrum along that length. The ratio of the lengths on either side of the fulcrum will determine the ratio of forces at either end. The length of the lever will dictate the total force possible. For a lever of length L divided into lengths a and (L - a) by the fulcrum (where a is the length of the lever between the fulcrum and the object you want to apply force to), the mechanical advantage will beM.A = (L-a)/aThe longer the lever, the bigger you can make the numerator of that fraction while keeping a unchanged.


How does a lever increase the mechanical advantage?

It has to do with a type of force called torque. When you push down on a lever, the force you push with is multiplied by the length of the lever to produce a torque. If you have a very long lever, then you are multiplying your pushing force by a big number and can produce a big torque. It's an easy way to get a large force with little effort.