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Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
The centripetal acceleration is equal to velocity squared over radius. a=v^2/r
Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)
As an object goes round in a circular path, then its velocity will along the tangent at that instant. But centripetal acceleration is normal to that tangent and so along the radius of curvature. As acceleration is perpendicular to the velocity, the direction aspect is ever changing and so the object goes round the circular path.
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
Centripetal Acceleration is the ratio of the square of the velocity and radius ac=v2/r So if we change the velocity of the circulating object or change the radius of the revolution, centripetal acceleration is changed
Use the formula for centripetal acceleration: velocity squared / radius.
The centripetal acceleration is equal to velocity squared over radius. a=v^2/r
Force (newtons) = mass (kg) * acceleration ((m/s)/s) but > acceleration in a circle = velocity 2 / radius So > (centripetal) force = mass * (velocity 2 / radius)
acceleration, a = velocity squared / radius(a = v^2 / r)
You can calculate the centripetal ACCELERATION with one of these formulae: acceleration = velocity squared / radius acceleration = omega squared x radius Acceleration refers to the magnitude of the acceleration; the direction is towards the center. Omega is the angular speed, in radians per second. To get the centripetal FORCE, you can use Newton's Second Law. In other words, just multiply the acceleration by the mass.
As an object goes round in a circular path, then its velocity will along the tangent at that instant. But centripetal acceleration is normal to that tangent and so along the radius of curvature. As acceleration is perpendicular to the velocity, the direction aspect is ever changing and so the object goes round the circular path.
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
With regard to Newton's First Law only, about all you could say is that if an objecthas no centripetal force acting on it, then it continues in constant, uniform motion.
Centripetal force is = mass * velocity square divided by radius
That depends what you will remain constant: the angular velocity, or the speed. Here are two formulae that can help you decide: acceleration = speed squared / radius, and acceleration = angular velocity squared times radius. Angular speed should be measured in radians in this case. Angular speed is equal to 2 x pi x (revolutions per second). From the above formulae, it clearly follows that: (a) If you maintain the speed constant (and thereby reduce angular speed, a larger radius means less centripetal acceleration. (b) If you maintain the angular speed constant (and thereby increase the speed), a larger radius means more centripetal acceleration.