Best Answer

There are 2.54 centimeters in one inch. First, I would find the square footage of each tile.

(15/2.54)*(59.5/2.54)=(5.906*23.425)=138.348 square inches per tile

Now, we would divide that number by 144 (the number of square inches in a square foot) to find the square footage of each tile (138.348/144=.96sqft/tile)

Now divide your total you want to cover (428sqft) by your sqft/tile (.96sqft) and you get 445.83, so, 446 tiles to cover the area desired.

If you're laying it, I would figure in 10% for waste, making your total 491 tiles.

...and that is without grout joints :)

Study guides

☆☆☆☆☆

Q: How many 15cm X 59.5cm tiles do you need to cover 428sq feet and can yo show me how to convert?

Write your answer...

Submit

Still have questions?

Related questions

You would need a total of 89 tiles (88.88 tiles exactly) with those measurements to cover that area.

The number of tiles needed to cover the floor is a function of the size of the tiles

The amount of tiles needed to cover a floor will depend on the size of the floor.

49 tiles

30 tiles! But you'll need more than 30 tiles to cover wastage, breakage, etc.

Depends on how big the tiles are.

it would be 81 tiles

76.6 tiles

67 tiles.

6,144 tiles !

can you completely cover a 3ftx6ft area with 2ftx2ft tiles

start with 38 tiles.

People also asked