There are 2.54 centimeters in one inch. First, I would find the square footage of each tile.
(15/2.54)*(59.5/2.54)=(5.906*23.425)=138.348 square inches per tile
Now, we would divide that number by 144 (the number of square inches in a square foot) to find the square footage of each tile (138.348/144=.96sqft/tile)
Now divide your total you want to cover (428sqft) by your sqft/tile (.96sqft) and you get 445.83, so, 446 tiles to cover the area desired.
If you're laying it, I would figure in 10% for waste, making your total 491 tiles.
...and that is without grout joints :)
The number of tiles needed to cover the floor is a function of the size of the tiles
The amount of tiles needed to cover a floor will depend on the size of the floor.
start with 38 tiles.
616 3x6 inch tiles are needed to cover exactly 77 square feet.
90 tiles.
The number of tiles needed to cover the floor is a function of the size of the tiles
You would need a total of 89 tiles (88.88 tiles exactly) with those measurements to cover that area.
The amount of tiles needed to cover a floor will depend on the size of the floor.
30 tiles! But you'll need more than 30 tiles to cover wastage, breakage, etc.
49 tiles
Depends on how big the tiles are.
it would be 81 tiles
6,144 tiles !
67 tiles.
76.6 tiles
In order to answer this question, we need to convert the dimensions of the tiles into ft. This makes all units consistent, and so easier to work with. There are 12 inches in a foot, and so to convert from inches to feet you need to divide by 12. In this case the tiles are 18x18, so divide this by 12 and you get 1.5ft x 1.5ft This means the tiles have an area of 2.25 sq ft. To find how many are needed for 800 sq ft, you just divide: 800/2.25 = 355.555555... Therefore, you would need 355.5 recurring tiles to cover the whole area.
can you completely cover a 3ftx6ft area with 2ftx2ft tiles