How many ATP are produced in Glycolosis and the kreb cycle and then electron transport chain?

Answer 1

The ATP yield in glycolysis is 2, citric acid cycle is 2, and the electron transport chain (ETC) is 34. ATP created from ETC was originally from the NADH and FADH2. In glycolysis and the citric acid cycle it was pyruvate oxidation.

Answer 2

You've got to be shi tting me. This isnt a high school homework question.

Glycolysis alone yields 2 molecules of ATP per glucose molecule

The complete breakdown via the citric acid cycle of the products of glycolysis yields approximately 34 more molecules of ATP.

The electron transport chain is integral and inseparable from the citric acid cycle, as well as from photosynthesis. It is part of the mechanism that yields ATP, but does not directly yield ATP itself.

Answer 3

1) Glycolosis uses 2 ATP to produce 4 ATP for a net gain of 2ATP. It also yields 2 NADH. Then, Pyrivic acid from glycolisis forms acetyl CoA producing 2 more NADH.

2) The Krebs Cycles yields 2 ATP and 6 NADH and 2 FADH2

3) The electron transport chain then oxidizes NADH and FADH2 to yield ATP. Each NADH produces about 3 ATP and each FADH2 produces about 2 ATP.

So the net production of ATP per glucose is 2ATP+2ATP=4ATP and

2NADH+2NADH+6NADH=10NADH 10NADH ~28 to 30ATP and

2 FADH2=4ATP, which is 36-38 ATP.

Answer 4

Glycolysis, as the name implies, is the lysing or cutting of glucose. To get this reaction started requires an input of energy, much the way starting a fire requires a match. The heat from the burning is greater that that of the match used to start it.

To start the reaction requires 2 ATP molecules. The breaking of the bonds in glycolysis yields 4 ATP molecules.

Answer to your question is 4 ATP output minus 2 ATP to get it started gives a net production of 2 ATP molecules.

Answer 5

compare the ATP yields of glycolysus, the citric acid cyle, and the electron transport chain.

Answer 6

Two six-carbon molecules.

Answer 7

the production of ATP

Answer 8

36 to 38 ATP are produced.

Answer 9

38