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Thermal energy is heat. It's what melts substances, changes temperatures, or vaporizes substances. It is measured in calories, joules or british thermal units. 252 calories = 1 b.t.u.,It takes 144 btus to melt 1 pound of ice at 32 degrees, 180 btus to raise 1 pound of water in temperature from 32F to 212F and 970.2 btus to make 1 pound of steam at 212 degrees.It takes 80 calories to melt 1 gram of ice at 0 degrees C, 100 calories to raise 1 gram of water in temperature from 0C to 100C and 538.6 calories to make 1 gram of steam at 100 degrees C.the calorie is equal to 4.1868 joules so that:It takes 334 joules to melt 1 gram of ice at 0 degrees C, 418.68 J to raise 1 gram of water in temperature from 0C to 100C and 2255.0 J to make 1 gram of steam at 100 degrees C.Answer'Thermal energy' is an obsolete term, long replaced by the term, 'internal energy'. Heat is not the same thing as internal energy, but is described as 'energy in transit' between a warmer body and a cooler body. In SI, all forms of energy, including energy in transit, are measured in joules.The British Thermal Unit (BTU) is an imperial unit used rarely outside the United States. The calorie is an obsolete unit used to measure energy in the cgsA system of measurement (despite this, for some reason, the food industry clings onto this unit, expessing the energy available from food in kilocalories).
10.28
2KW conversation in BTU
W x 0.00095 = Btu
Depends on the temperature of the water. If it is 32 degree water and you want 32 degree ice then you need a -144 BTU loss to change state from liquid to solid. It takes 1 BTU to raise the temperature of 1 pound of water 1 degree (F). If the water is 82 degrees then you would need a -50 BTU loss (+) 144 BTU to change state. TOTAL WEIGHT OF WATER (X) 1 BTU (X) Degrees desired of change. If it is ICE to WATER then it is the TEMP of ICE (X) .5 BTU (X) NUMBER OF DEGREES INCREASED = TOTAL BTU needs. If you change state in the process you have to add 144 BTU for 32 degree ICE to 32 degree WATER and 970 BTU for 212 degree WATER to 212 degree STEAM but only when you change state.
6,520 Btus
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
25
From high school science class; it takes 144 BTUs to melt a pound of ice. That takes it to 32 degrees F. To then raise the temp to 72 deg., would take about 40 more BTUs.
100 BTU if it's Fahrenheit
1320 btu`s
Heat. Ice, solid water, at 32 degrees F needs 144 btus of heat per pound to liquify completely. Water at 212F needs 970.3 btus per pound to evaporate completely into dry steam. Water vapor (visible steam), in air, {say from a pot} is actually about 3 to 10% dry steam and only required about 28 to 100 btus per pound to vaporize and become airborne, This is an odd characteristic of water, that varying proportions of dry steam will carry large amounts of liquid water along with it as it evaporates (Wet Steam).Water can exist in all three states at the same time, in the same general vicinity. Ice floats on liquid water and the air around it will also contain some amount of water vapor (humidity).
313 Btu
A 100 pound propane tank has a capacity of 2,160,509 BTUs
The question cannot be answered because:the temperature scale being used has not been specified,There is no normal temperature scale in which you can have ice at 32 degrees and steam at 82 degrees without large changes in pressure. If changes in pressure are permitted then there is no simple formula to calculate the amount of heat (btus) required.
There are 1078.9 BTUs.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.