It takes 180 BTUs to raise 1 pound of water from 32 degrees Fahrenheit to 212 degrees Fahrenheit to convert it completely into steam. This change in temperature includes heating the water from its freezing point to boiling point, then undergoing phase change from liquid to gas.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
1 pound of water at sea level can produce approximately 26.8 cubic feet of steam.
One pound of steam weighs the same as one pound of water, which is approximately 16 ounces or 0.45 kilograms.
To raise the temperature of 1 pound of water by 1 degree Fahrenheit, it requires 1 BTU (British Thermal Unit). Therefore, to heat water by 10 degrees, it would require 10 BTUs per pound of water. This value may vary slightly depending on the specific heat capacity of the water.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
Burning 100g of water at 100 degrees would release more energy than burning 100g of steam at 100 degrees, as water at a higher temperature has more thermal energy to be released. Burning water at 100 degrees would first need to raise its temperature to its boiling point before converting it into steam.
To transform one pound of ice at 30°F into one pound of steam at 214°F, you need to consider several steps: melting the ice to water, heating the water to 212°F, converting the water to steam, and then heating the steam to 214°F. The total energy required can be calculated using specific heat values and latent heats. Roughly, this amounts to about 1,000 Btu for melting, 90 Btu for heating the water, 1,000 Btu for vaporization, and 2 Btu for heating the steam, totaling around 2,092 Btu.
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
1 pound of water at sea level can produce approximately 26.8 cubic feet of steam.
One pound of steam weighs the same as one pound of water, which is approximately 16 ounces or 0.45 kilograms.
at 100 degrees liquid water will go to steam and steam will go to liquid water
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
It has to give up quite a lot of heat. A pound of steam carries 940 btu's of heat that has to be transferred out to end up with one pound of water at the same temperature. It only takes 180 btu's to raise water from 32 degrees Fahrenheit to 212 degrees.
To raise the temperature of 1 pound of water 1 degree F requires one BTU. If one pound of water at 62 degreesF is raised to 212 degreesF liquid, 150 BTU's would be required. When one pound of water at 212 degreesF is converted to steam, an additional 970 BTU's are absorbed. The total number of BTU's absorbed in converting one pound of water at 62degreesF to steam is 1,120 BTU's. Water weighs 8.33 pounds per gallon One gallon of water, when converted to steam, will absorb 9,330 BTU's (8.33 times 1,120)