A british thermal unit (btu) is the amount of heat required to raise 1 pound of water 1 degree fahrenheit. How many btu's would be required to raise 45 pounds of water 18 degrees fahrenheit?
Solution 44430
Amount of heat
= {(1 btu) / [(1 lb)(1 F)]} * (45 lb) * (18 F)
= 810 btu
202.3 btu
According to Keenan and Keyes, 1 lb of water at 100psia requires 298.4 btu to raise it's temperature from 32 degrees to 327 degrees F. that is 1.0115 btu per pound. So 2 lbs of water would require 202.3 btu to raise it's temperature at 100 psia 100 degrees F. (from between 32F-227F to a higher temperature between 132F-327F)
At 100psia any addition of heat to water at 327F will result in the generation of steam and no increase in temperature.
**Note: closed feed water heaters (heat exchangers) work on this principle of cooler water under pressure being heated to boiler temperatures to avoid thermal shock to the boiler, for a practical application. It is generally assumed that one pound of water requires 1 btu of heat to raise it's temperature 1 degree despite it's pressure. This assumption is only slightly incorrect at low pressures (less than 600 psia), but more flawed at higher pressures, as evidenced by heat-entropy tables showing a larger increase in heat required as the pressures approach critical pressures. (water at 3206 psia requires 902.7 btu to raise it's temperature 671.4 degrees or 1.3445 btu per pound [at this pressure water converts directly to steam with no latent heat required]).
45 pounds x 18* F = 810 BTU’s
810
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
what is the answer to this
1 calorie is needed to raise 1 g of water 1 °C. 350 * 22 = 7700 calories ■
Assume the water is initially at 40 F and 14.7 psia.m = ( 1.0 gal ) ( 1.0 ft^3 /7.4805 gal ) ( 62.43 lbm / ft^3 ) = 8.346 lbmQ = Delta U = ( m ) ( Cv ) ( T2 - T1 )Q = ( 8.346 lbm ) ( 1.00 Btu / lbm - Fdeg ) ( 200 F - 40 F ) = 1335 Btu
Answer:A BTU is the amount of heat energy required to raise 1 pound of water by 1 degree Fahrenheit. So a 30,000 BTU burner can heat 30,000 pounds of water by 1 degree Fahrenheit. Any multiple of the amount of water and the temperature rise that yields 30,000 is equivalent.And 30 000 BTU equal 31 651,68 kilojoules.Usually it is more meaningful to rate a heating device in BTU/hour.
25
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
The answer depends on the unidentified substance whose temperature is to be raised.
If you're in Celsius, 13459.5 Btu's. If you're in Fahrenheit, 12632.5 Btu's.
That's going to depend on how much water you're responsible for. Teacup at 60 degrees . . . very few BTU. Swimming pool at 60 degrees . . . many more BTU. It's also going to depend on whether you're talking about Celsius or Fahrenheit degrees. Fahrenheit degrees . . . fewer BTU. Celsius degrees . . . more BTU. (Also, the water will escape as you pass 100.) In general, one BTU is approximately the energy required to raise the temperature of 1 pound of water 1 degree Fahrenheit. You can take it from there, when you reach the job site and determine the exact scope of the work.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The amount of energy that is required to 160 cfm of air from 10 to 170 degrees F is 200 btu. T he formula is weight x specific heat x temperature difference so we have10 pounds x 1.00 x 2010 for 10 pounds of water.
15480.80
2250
13,455 J
700
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!