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This question is a little confusing in that BTUs are not generated in raising the temperature of anything; the input of heat is required. And if the questioner meant required instead of generated, then the question is still unanswerable as the amount of water must be specified, AND the starting temperature must be specified.
Depends on the temperature of the water. If it is 32 degree water and you want 32 degree ice then you need a -144 BTU loss to change state from liquid to solid. It takes 1 BTU to raise the temperature of 1 pound of water 1 degree (F). If the water is 82 degrees then you would need a -50 BTU loss (+) 144 BTU to change state. TOTAL WEIGHT OF WATER (X) 1 BTU (X) Degrees desired of change. If it is ICE to WATER then it is the TEMP of ICE (X) .5 BTU (X) NUMBER OF DEGREES INCREASED = TOTAL BTU needs. If you change state in the process you have to add 144 BTU for 32 degree ICE to 32 degree WATER and 970 BTU for 212 degree WATER to 212 degree STEAM but only when you change state.
That depends on what the starting temperature of the water is,and what temperature you want it to reach.If you expect to get a number, you must first give the necessary numbers.
10.28
W x 0.00095 = Btu
313 Btu
6,520 Btus
That will completely depend on how much water there is.
25
2250
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
144
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
100 BTU if it's Fahrenheit
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water