delta T x specific heat x mass Delta T = change in temperature specific heat of water = 4.1813 J/gC Mass= 45.0g 48C-14C=34C 34 C x 4.1813 J/gC=142.1462 J/g 142.1462 J/g x 45g = 6397.389 J restricting us to three significant digits = 6.40 x 10^3 J
q(joules) = mass*specific heat*change in temp.
A few conversions for my benefit.
14.00 kg = 14000 grams
q = (14000 g)(4.180 J/gC)(46.5 C - 24.8 C)
= 1269884 Joules (1 kj/1000 J)
= 1270 kilojoules
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4.184 J/g/K so 4.184 x 46 x 14 = 2694.5 Joules
123.2
These are not temperature numbers but specific heat numbers. They mean that it takes 4.184 Joules and 0.387 Joules respectively to raise water and copper of one gram by one degree celsius. So, as you can see, it takes a lot more heat to raise the temperature of water than it does of copper. Water has a very high specific heat.
The metric unit of temperature is the degree Celsius (°C).
Specific temperature is an amount of heat per unit mass required to raise the temperature by one degree Celsius.
specific heat(; your welcome!
4,200 J/kgC (83-4) x 8kg x 4,200 = 2,654,400 joules
The answer is 53,683 kJ.
15.37684 joules
The specific heat capacity of water is 4.184 J/g°C. The change in temperature is 70°C - 20°C = 50°C. Using the formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we get Q = 74g * 4.184 J/g°C * 50°C = 15,535.2 Joules.
To find the temperature increase, you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat energy transferred, ( m ) is the mass of the substance, ( c ) is the specific heat capacity of the substance, and ( \Delta T ) is the change in temperature. Rearrange the formula to solve for ( \Delta T ) by dividing both sides by ( mc ): ( \Delta T = \frac{Q}{mc} ). Substitute ( Q = 889J ), ( m = 705g = 0.705kg ), ( c = 4.18 J/g°C ), and calculate to find the change in temperature.
It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?
To find the mass of the iron sample, you need to know the specific heat capacity of iron. Given that the heat energy required to raise the temperature is 562 Joules, you can use the formula: heat energy = mass x specific heat capacity x temperature change. With the specific heat capacity of iron (0.45 J/g°C), you can calculate the mass of the iron sample.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
Energy required to raise 1 gramme of water by 1 degree C = 1 calorie also, 1 calorie = 4.186 Joules
I will use this formula, the convert. q( in Joules ) = mass * specific heat Au * change in temp. q = nCT q = (150 grams)(0.129 J/gC)(175 C - 25 C) = 2902.5 Joules Now, 1 calorie = 4.184 Joules 2902.5 Joules (1 calorie/4.184 Joules) 694 calories required
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules