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delta T x specific heat x mass Delta T = change in temperature specific heat of water = 4.1813 J/gC Mass= 45.0g 48C-14C=34C 34 C x 4.1813 J/gC=142.1462 J/g 142.1462 J/g x 45g = 6397.389 J restricting us to three significant digits = 6.40 x 10^3 J

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15y ago
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12y ago

q(joules) = mass*specific heat*change in temp.

A few conversions for my benefit.

14.00 kg = 14000 grams

q = (14000 g)(4.180 J/gC)(46.5 C - 24.8 C)

= 1269884 Joules (1 kj/1000 J)

= 1270 kilojoules

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13y ago

4.184 J/g/K so 4.184 x 46 x 14 = 2694.5 Joules

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Anonymous

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4y ago

123.2

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Q: How many Joules of heat are necessary to raise the temperature of 46 g of water from 100.0 Celsius to 114.0 Celsius?
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