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What are the spectator ions in Bal2 plus Na2SO4?
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
How many moles of Na SO4 are in 25.0 of this compound?
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
What happens to the bound na plus and cl- ions as they enter the water?
dgrrturdd
Is Na2SO4 a ionic compound?
Yes. The charge on Na (sodium) ions is 1+ and the charge on a SO4 (sulfate) ion is 2-. So to balance out the charges 2 sodium ions are needed for every sulfate ion.
Is NA plus an electrolyte?
Yes, Na+ can only exist as an ion in a solution and, in the body, ions in solutions are called electrolytes.
What are the spectator ions in Bal2 plus Na2SO4?
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
What are spectator ions in Na plus plus OH- plus Cl- H2O plus Na plus plus Cl?
Na+ and Cl- are spectator ions.
How do you balance CuSO4 plus Na?
CuS04 + 2Na -> Na2SO4 + Cu
How many moles of Na plus ions are there in a moles of NaCl?
one
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?
What is the symbol of sodium thiosulfate?
The chemical formula for sodium oxide is Na2O. It is an ionic compound and the ions present are Na+ and O2-.
What ions are present in sodium sulphate solution?
Dissolving in water (aq):Na2SO4 --> 2(Na+)aq + (SO42-)aq
Na plus H2SO4 what is the balanced equation for this?
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
Na2SO4 is a typical ionic sulfate containing how many Na ions and SO42- ions?
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
What is the total molar concentration of ions in a 0.350 M solution of the strong electrolyte Na2SO4 assuming complete dissociation?
1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.
NA plus ions enter cells by?
binding to Na+ carrier proteins
