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7: 27 = 128
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How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
How many memory address does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many address lines can access a 16MB memory?
for 16 MB memory has 24 address lines
Minimum number of address lines needed to access a physical memory of 1GB?
You need 30 address lines to access 1G of memory. 230 = 1,073,741,824. log2 (1,073,741,824) = 30.
How many memory addresses does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many address lines are require to access 128MB of memory?
ANSWER There are 2128 combinations of addresses. This is about 3.4 x 1038 locations. Assuming each address holds a 32-bit word, that's 1.2 x 1039 bytes. That's a LOT of memory.
How many address lines are required if micro processor has to access 2kb memory?
2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required
How do you interface a code memory of 128 KBytes to a controller having 16 address lines?
use bank-switching, or (slower) a shift register.
How many Address lines and data lines of microprocessor and microcontroller?
Microprocessor has 16 address lines and microcontroller has 20 address lines
A RAM has a capacity of 64Kx16 how many address lines will be needed for this RAM?
you require 16 input line and 16 output line and 16 address line. Because 64 K = 26 X 210 = 216 so, 16 address lines Here N = 16, so 16 data lines will be there. .
How many address lines are required to address 64 kbytes of memory?
You need 12 address lines to access 4K of memory. 212 = 4096. log2 (4096) = 12.
A microprocessor has 24 parallel address lines How many memory locations can the processor address?
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
