It requires 30 address bits to address 1GB of RAM.230 = 1,073,741,824
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
You need 30 address lines to access 1G of memory. 230 = 1,073,741,824. log2 (1,073,741,824) = 30.
You cannot address 1GB memory with the 8085 or the 8086/8088 without some kind of external demultiplexor that is software controlled. The address bus on the 8085 is 16 bits, giving addressibility of 64KB; while the address bus on the 8086/8088 is 20 bits, giving addressibility of 1MB. To address 1GB, you need a 30 bit address bus.
1000kb = 1mb 1000mb = 1gb 1,000,000kb = 1gb
1Gb
On a Flip Mino HD 1GB = 30min.
1GB = 1024 MB 1MB= 1024 KB So 1GB= 1048576 KB
1024mb (megabits) = 1gb (gigabits)
just get a 1gb stick.
no, i think it required like 5-7 gb or something.
About 1000.