You really need to know the line voltage (VL) involved. Provided the load is balanced, to find the line current, you need to divide the load (in watts) by (1.732 x VL). Incidentally, the correct symbol for kilowatts is kW, not Kw!
1KW=1000*1.736*440*1(Ampere)*p.f (for 3 phase). Here power factor is required for solution.
The formula you are looking for is Amperage = kw x 1000/1.73 x Voltage x pf. pf is power factor. Use .9 as a reference for power factor.
That can be split into three 254 v single-phase circuits each carrying 40 amps and the total VA is 30.5 kVA. Therefore the power is up to 30.5 kW depending on the power factor of the load.
Here is the Formula for you to find out you yourself. Power=3IV*Power Factor of that motor. ( The value for I=Current and V=Voltage) must be phase values.
The formula you are looking for is I = kW x 1000/1.73 x E x pf. The power factor (pf) value of .9 will be used. Amps = 60 x 1000/343 = 60000/343 = 175 amps.
Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
The formula you are looking for is I = W/E. Amps = Watts/Volts.
90 kW on 480 volts single phase would be 187.5 amps. On 480 v 3-phase it would be 108 amps.
A voltage of 240 volts is not a common three phase voltage. Single phase kva of 240 voltas and 50 amps is I x E/1000 = 240 x 50 = 12000/1000 = 12 kVa -- Assuming the 240 volts is phase to phase voltage, and this is a three phase application: KVA = V*I*sqrt (3) = 20.78KVA
You must rephrase your question to make it more specific. <<>> The formula to use to find KVA in a three phase system is, KVA = Amps x Volts x 1.73/1000.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
500,000 watts/240 volts = 2,083.34 Amps (single phase)
The maximum single phase HP motor listed in the CEC is 10 HP. At 115 volts 100 amps and 230 volts 50 amps.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
Just multiply. (Note, this assumes no phase difference.) <<>> The formula you are looking for is W = I x E. Watts = Amps x Volts.
Using the formula: Amps = Watts/Volts look up the wire size needed in the national electric code book for the amperage of the device. This formula only works for single phase current. If you are using 3 phase, look in the book. In general, 15 Amps or less: 14 Ga Copper wire. 20 Amps or less 12 Ga. 30 Amps or less 10 Ga. Anything more than 30 amps, look it up in the book.
This depends on what voltage the range is rated for and if it is single phase or three phase. At 220 volts single phase it is about 60 amps, 240 v single phase , 53 amps and at 480 v three phase about 15 amps.
Amperes when kva is shown. The formula is, Amps = kva x 1000/1.73 x volts.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
Do the math: Amps x Volts = Watts. Your house is mostly 120V and each circuit is usually 15amps (not counting large appliances).
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.