8,33 Amps
it draws 210 amps
1/2 amp.
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
Use the formula A = W/V, where A is amps, W is watts and V is voltage.
8,33 Amps
it draws 210 amps
It is drawing .06 amps.
It would be at least 250 amps, maybe 300 amps.
1.25 amps
1/2 amp.
Have to know the wattage or resistance of the lamp to answer this question.
Multiply the vots by the amps to find the volt-amps. Or divide the volt-amps by the voltage to find the amps.
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
Use the formula A = W/V, where A is amps, W is watts and V is voltage.
Volts * Amps = Watts 12 Volt * 2 amp = 24 Watts
No, unless you can set it low and can be assured that it wont use more than say 4000watts, the welder might momentarily use more power than what you set it to, it should not wreck the welder i would imagine unless it is a fancy mig welder or something, set the welder low you should be fine but for high end use she should be firing out 8 or 9kw so keep it low if you must.