46A
AnswerAs 15 horsepower is the output power of the machine, you will need to know its efficiency at that output in order to determine its input power. Without that information, you cannot determine its current draw.
first of all convert 5hp to wattage
since 1hp=745.7watts;then 5hp=5*745.7=37285watts=3.7285KW
Thus;power=current*voltage
3.7285=I * 240
therefore; I=3.7285/240
=0.015535A
=15.53mA
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At the risk of being chastised by an administrator, I'd like to comment on the math above.
IF YOU CANNOT DO THE MATH, DON'T ANSWER MATHEMATICAL QUESTIONS.
First, 5 times 745.7 is 3728.5.
Second, you do not convert this to KW before plugging it into the equation,
power = current * voltage. So the proper equation is 3728.5 = I * 240.
Solving this equation gives you 15.54 AMPS, not mA.
Answer for USA, Canada and countries running a 60 Hz supply service.
However (yes, it gets better) the NEC shows that this motor would use as much as 28 amps at full load (FLC). The 5hp is a RATING and as we all know, ratings are always based on one or more assumptions and we can see that full load is obviously not one of them.
The NEC requires that CONDUCTORS for this motor be sized for no less than 35 amps (125% of FLC), and that this motor not be connected to an INVERSE TIME BREAKER larger than 70 amps (250% of FLC). This motor might be successfully operated on 10 AWG wire. Yes, 10 AWG wire will carry 35 amps, though it cannot be placed on a breaker larger than 30 amps.
As you can see, sizing a circuit for a motor is a complicated process. There are short cuts to this process but there is only one right way.
Properly installing a 5 horsepower, 240v motor requires a competent electrician.
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As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.
IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
around 43 amps , single phase(regular house power) 240volts
Volt amps is the same way of saying watts. This is seen in the formula Watts = Volts x Amps. Using the formula I = W/E we transpose I = 20000/240 = 83.33 amps.
That's a powerful motor, and would need a supply greater than 13 amps at 240 volts, also the conversion might be difficult. I have a feeling that you would be better off finding out how powerful a motor you would need for the task you have, then buying a suitable 240 volt motor. You are heading into territory where you should really consult a qualified electrician.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
24.87amps 1 hp=746 watts P=IxV ... (746x8)/240
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
It would be at least 250 amps, maybe 300 amps.
12/240, 0.05 amps, maybe about 30% more because of the poor power factor of small transformers.
AWG #10 copper on a 30 amp breaker.
no
The formula for amps is I = W/E. Amps = 40/240 = .17 primary amperage. For the secondary amperage I = W/E. Amps = 40/24 = 1.7 amps.
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
Minimum current would be 10000 divided by 240 but it might be up to 30% more if the load has a poor power factor.
Current (Amps) = Power (Watt)/Voltage (V) Therefore a 4500W heating element will draw 18.75A = 4500W/240V