Check the current draw that is on the label of the ballast.
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
Look on the ballast inside of the fixture. There is an amperage and a voltage on the ballast label. Use this equation to find the wattage. W = I x E, Watts = Amps x Volts. This will give you the answer that you are looking for.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
Watts = Amps x Volts. Amps = Watts/Voltage. Amps = 2500/apply voltage here.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
It would be pretty much undefined, since the filament of the halogen bulb would fail immediately then there would be an open circuit with no current draw. <<>> The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
Look on the ballast inside of the fixture. There is an amperage and a voltage on the ballast label. Use this equation to find the wattage. W = I x E, Watts = Amps x Volts. This will give you the answer that you are looking for.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
Watts = Amps x Volts. Amps = Watts/Voltage. Amps = 2500/apply voltage here.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
You would need to use a #12 copper conductor to continuously draw 14 amps at 120 volts.
10 Amps. Amps=Watts/Volts
A2.2 kW kettle will draw 9.16 amps at 240 volts. I = W/E. Amps = Watts/Volts.